Calculate the standard free-energychange of the reaction catalysed by theenzyme phosphoglucomutase Glucose-1-P = Glucose-6-P, given that, startingwith 28.29 mM Glucose-1-P and noGlucose-6-P, the final equilibrium mixtureat 25°C and pH=7.0 contains 9.77 mMGlucose-6-P and the remaining Glucose-1-P. Give the answer in J/mol.K to onedecimal place.

Reaction in the given question is proceed as Glucose-1-phosphate →→ Glucose-6-phosphate…

Answered: Calculate the standard free-energy…

Biochemistry

9th Edition

ISBN:9781319114671

Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Chapter1: Biochemistry: An Evolving Science

Section: Chapter Questions

Problem 1P

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Calculate the slope on a Lineweaver-Burk plot (Km / Vmax) for the lactase reaction with inhibitor X. (inhibitor X changes lactase activity to a Vo of 0.10 mM per minute when [S] = 1.0 mM, and a Vo of 0.133333333333 mM per minute when [S] = 2.0 mM) 0.20 per minute 0.50 per minute 1.0 per minute 2.0 per minute 5.0 per minute
The Keq (25C) of the reaction below is 635.67. Fructose 1,6-biphosphate <-->fructose -6-phosphate + Pi. a) What is the standard Gibbs free energy change for this reaction? b) if the concentrationof fructose 1,6 biphosphate is adjusted to 0.85 M and that of fructose 6 phosphate and phosphate adjusted to 0.055 M, what is the actual free energy change
24. Hexokinase catalyzes the phosphorylation of glucose from ATP, yielding glucose-6-P and ADP. The standard-state free energy change for hydrolysis of glucose-6-P is -13.9 kJ/mol. Calculate the standard-state free energy change and equilibrium constant for the hexokinase reaction. AG" for ATP hydrolysis -31.5 kJ/mol
Utilising the provided class data generate the following graphs: I) Michaelis Menten; II) Lineweaver-Burk; and III) Hanes-Woolf. Ensure that you clearly label each graph,and add the relevant trendlines with equations. Table 1: Class data demonstrating the Absorbance at 700nm obtained for the alkaline phosphatase enzyme reaction Table 1 tube Abs700mm 1 0.000 2 0.060 2 0.090 4 0.140 5 0.190 6 0.250 7 0.290 The equipment we used are • 20mM Tris Buffer pH 8.5 • 33mM MgCl2 • Alkaline Phosphatase (2mg/ml) in 20mM Tris Buffer pH 8.5 • 4mM Glucose-1-phosphate • Acid Molybdate pH 5.0 • Reducing Agent • Distilled Water • Glass Test tubes • Tube Rack • Cuvette • Pipettes and Tips • Water bath set to 37oC The method we used is Method/Protocol: 1. Read the protocol in its entirety before starting. Take note of any additional information that appears in subsequent steps that may influence how previous steps are performed. 2. Using glass tubes, generate the reactions mixtures…
3. 1,3-bisphosphglycerate has a high energy bond that can be used to phosphorylate ADP to make ATP according to the equation below. The free energy of hydrolysis of 1,3- bisphophoglycerate and ATP under standard conditions are -49.4 kJ/mol and -30.5 kJ/mol, respectively. If the [ATP] to [ADP] is about 4 in the cell, how much 1,3-bisphophoglycerate is needed relative to 3-phosphoglycerate to keep this formation of ATP spontaneous? -203PO. H- -OH -OPO3-² + ADP H- -OH -OPO3-² + ATP
The equation of the double reciprocal plot is y = 0.5294 x + 1.4960. What is the value of vmax (in M/s)? The substrate concentration is given in units of molarity (M) and reaction velocity has units of molarity per second (M/s). (Report to three significant figures)
From a kinetics experiment, kcat was determined to be 295sec-1. For the kinetic assay, 0.3mL of a 0.25mg/mL solution of enzyme was used, and the enzyme has a molecular weight of 125,000 g/mole. Assume a reaction volume of 3mL. Calculate Vmax (µM∙min-1) for the enzyme and catalytic efficiency ( in M-1sec-1) for the enzyme. The Km for the enzyme was determined to be 2.55 x 10-2M.
Use the Michaelis-Menten equation to complete the enzyme kinetic data set, whenKm is known to have a value of 1 mmol L−1 [S] (mmol L−1) Vo (μmol L−1 min−1) 0.5 50 1.0 2.0 3.0 10.0
You obtain a calculated Vmax of 4.26uM/s and a Km of 122.5uM from a kinetics experiment performed using 0.5uM enzyme. What is the catalytic efficiency of this enzyme?
The enzyme, fumarate, has the following kinetic constants: k 1 k 2 k -1 where k 1 = 10 9 M -1 s -1 k -1 =4.4 x 10 4 s -1 k 2 = 10 3 s -1 a. What is the value of the Michaelis constant for this enzyme? b. At an enzyme concentration of 10 -6 M, what will be the initial rate of product"
Write a balanced equation for cach of the following reactions or reaction sequences. (a) The reaction catalyzed by PFK-2 (b) The conversion of 2 moles of oxaloacetate to glucose (c) The conversion of glucose to UDP-Gle (d) The conversion of 2 moles of glycerol to glucose (e) The conversion of 2 moles of malate to glucose-6-phosphate
[References) The AG" for the reaction ATP + H₂O ADP + P + H+ is -30.5 kJ mol'¹, Other organophosphate species also undergo hydrolysis of the phosphate moiety via a similar reaction. Determine the value of AG for the following reactions and indicate if the reaction will proceed spontaneously in the direction written if the reactants and products are initially in a 1:1 molar ratio. a. ATP + Glucose ADP+ Glucose-1-phosphate AG⁹¹ = kJ mol-1 The reaction is (The hydrolysis reaction for glucose-1-phosphate is Glucose-1-phosphate + H₂0 Glucose + P + H+; AG-20.9 kJ mol ¹.) b. ATP + Glutamate Carbamoyl phosphate + ADP AG The reaction is kJ mol-1 (The hydrolysis reaction for carbamoyl phosphate is Carbamoyl phosphate + H₂0 Glutamate + P, + H+ ; AG¹ = -51.4 kJ mol ¹.) Submit Answer Try Another Version 3 item attempts remaining

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