Assume that an enzyme-catalyzed reaction follows the scheme shown:E + SESE + Pk₁ = 1 x 10%/M-s k-1 = 2.5 x 10%/s k2= 3.4 x 107sWhat is the dissociation constant for the enzyme-substrate, Ks?What is the Michaelis constant, Km, for this enzyme?What is the turnover number, Kcat, for this enzyme?What is the catalytic efficiency for the enzyme?If the initial Et concentration is 0.25mM, what is Vmax?

Michaelis Menten postulated that free enzyme reacts with the substrate reversibly to form an…

Answered: Assume that an enzyme-catalyzed…

Biochemistry

9th Edition

ISBN:9781319114671

Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Chapter1: Biochemistry: An Evolving Science

Section: Chapter Questions

Problem 1P

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In a major metabolic pathway involving the monosaccharide glucose, one of the reactions involve the conversion of glucose to glucose-6-phosphate summarized below together with accompanying free energy change: glucose + phosphate = glucose-6-phosphate + H,0 AG = 13.8 kJ · mol-1 (Reaction 1) In cells, the production of G6P (Reaction 1 above) is coupled to a reaction that involves the hydrolysis of ATP to ADP (shown below, Reaction 2) which makes the overall reaction much more favorable to the production of glucose-6-phosphate. ATP + H,O = ADP + phosphate (Reaction 2) Why do you think coupling the production of glucose-6-phosphate to the hydrolysis of ATP makes the overall reaction spontaneous? What can you say about the free energy change accompanying the hydrolysis of ATP (Reaction 2)?
How will a graph of reaction rate (V) vs. [substrate] for an allosteric enzyme differ from the hyperbolic plot characteristic of enzymes having Michaelis-Menten kinetics?
Given the following reaction and equation for the initial velocity of the reaction: k₁ k3 E+S ES E + P V=Keat [ES] = k3 [ES] k₂ where keat is the rate constant for the reaction which forms the product from the ES complex. Explain in words why the velocity is directly proportional to theamount of enzyme added in the presence of saturating substrate levels.
what concentration of a competitive inhibitor is required to yield 60% inhibition of an enzyme at a substance concentration of 1.0x10^-4 M. The Km for the enzyme is 22 uM and the Ki for the inhibitor is 59 uM. To what concentration must the substrate be increased to reestablish velocity at the uninhibited value?
at what substrate concentration is v= 5.0 mM s^-1 for the enzyme catalyzed hydrolysis of trehalose?
Derive an Equation that explains the realtionship between kE and kN with respect to the equilibrium constants provided in the reaction scheme provided below. Assume that the enzyme must bind with A before it binds with B. The two reactions are related by the following reaction scheme:provided below.
For some Enzyme, the Vmax is 18 micromols/min, Km is 400 microM. If the substrate concentration is 100 microM, what is the velocity of the reaction?
there are A-D questions to this picture set up. A) What enzyme catalyzes this reaction? B) What is Delta G, please answer in Joules, K=19 C) If concentration of Glucose-1_Phosphate is 48.82 uM at equalibrium, what is the concentration of Glucose-6-phosphate in uM? D) If the reaction is NOT at equalibrium, what is delta G at 25C if the concentration of Glucose-1-phosphate is 15.04 uM and concentration of Glucose -6-phosphate is 1.62 mM? please answer in Joules and in significant figures. *note, 10^3uM in 1 mM Thank you!!
Following is a Dixon plot for PNPP inhibition by inorganic phosphates. What answer choice shows the correct combination of the mode of inhibition and Ki of the EI complex? - Mixed inhibition, Ki= -21.2 uM - Mixed inhibition, Ki= 1/16.5 uM - Competitive inhibition, Ki= 16.5 uM - Competitive inhibition , Ki= -1/16.5 uM - None of the above
(b) You are investigating the effects of several agents on the activity of alcohol dehydrogenase. The enzyme activity data are shown in the table below. Construct a [substrate] vs. activity plot and a double-reciprocal plot for this enzyme. Be sure to label all axes. Determine the Vmax and KM for AD from the graphs in each type of plot. AD activity (nM/min) AD activity + agent A (nM/min) AD activity + agent B (nM/min) [Alcohol] (nM) 0.1 14 2 0.5 50 7 8. 1.0 65 10 30 2.0 72 12 45 4.0 80 14 62 8.0 85 15 75 32.0 90 16 90
You begin to study enzyme Z, which catalyzes a simple reversible reaction that interconverts compound S and compound P. You observe that the ∆G´° for the S to P conversion to be –6 kJ/mol, and that compound S has ∆G´° for binding to enzyme Z of –15 kJ/mol, while compound P has a ∆G´° for binding to enzyme Z of –13 kJ/mol. Please explain the effect of enzyme Z on conversion of S to P. (Your answer should include a graph qualitatively showing energy versus reaction progress; however, you still need to explain youranswer in words!) not sure how to make the correct graph.
When 10 micrograms of an enzyme with a molecular mass of 80,000 Daultons (grams/mol) is added to a solution containing its substrate at a concentration 100 times the Km, it catalyzes the conversion of 65 micromoles of substrate into product in 3 minutes. What is the enzyme's turnover number (in units of min-1)?

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