Calculate the milligrams of zinc and nickel present per milliliter in your original sample by taking the average of the two trials. To do this, determine the amount in moles that was in the 10-mL of diluted sample placed onto the column. Take this concentration and correct for the first sample prep dilution where you took the original unknown and diluted to 100 mL. Molarity of EDTA = 0.003298 M Ni: Trial 1= 20.80 mL Trial 2= 20.81 mL EDTA used in titration Zn: Trial 1= 31.18 mL Trial 2 - 21 80 ml E DTA UC ed in titration

Calculate the milligrams of zinc and nickel present per milliliter in your original sample by taking the average of the two trials. To do this, determine the amount in moles that was in the 10-mL of diluted sample placed onto the column. Take this concentration and correct for the first sample prep dilution where you took the original unknown and diluted to 100 mL. Molarity of EDTA = 0.003298 M Ni: Trial 1= 20.80 mL Trial 2= 20.81 mL EDTA used in titration Zn: Trial 1= 31.18 mL Trial 2 - 21 80 ml E DTA UC ed in titration

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Titrated with 0.3554 M NaOH True molarity of unknown: 0.5018 M Trial 1 Trial 2 trial3 The volume of acid added to flask (mL) 10.00 10.00 10.00 Initial buret reading (mL) 0.00 14.06 28.19 Final buret reading (mL) 14.06 28.19 42.30 Volume of base titrated into flask 14.06 14.13 14.11 calculated molarity of acetic acid in your unknown A) calculate the molarity of acetic acid in your unknown for each trial. b) choose the three trials that have molarities that agree within 1% of one another and use these three molarities to calculate average c)use the true molarity for your acetic acid solution from above. using the average molarity that you calculated above calculate the percent error for your unknown.
A student performed three KHP titrations in Part 1 in order to standardize their NaOH solution. They reported the following measurements: Mass of KHP + Vial Mass of 'Empty' Vial Final Burette Reading Initial Burette Reading Determination #1 16.7538 g 16.2649 g 21.67 mL 0.40 mL Determination #2 14.1709 g 13.5560 g 26.98 mL 0.31 mL Determination #3 15.6625 g 15.0833 g 26.04 mL 0.93 mL How many moles of KHC8H4O4 did they use in their second titration? Report your answer to the correct number of significant figures and only report the numerical value (no units).
Volume vinegar used (mL)= 5.00 mL % from labe= l5 % Molarity of NaOH = 0.0976 M Titration volume measurements Trial 1 Trial 2 Trial 3 Inital volume NaOH (mL) 0.69 0.86 0.16 Final volume NaOH (mL) 43.47 43.36 43.03 Volume NaOH used (mL) Average volume NaOH used (mL) Average volume NaOH used (L) Moles NaOH used (from avg volume) Moles CH3COOH Molarity CH3COOH (mol/L) Mass CH3COOH (g) % (m/v) CH3COOH in vinegar
You have a sample of approximately 100 mg/L of calcium carbonate and the standardized EDTA has a concentration of 0.00085 M. If you only want to spend approximately 15 mL of the titrant and add 25 mL of sample in the Erlenmeyer flask, can you use it or should you dilute it? the sample?, how much? Solution: No, 29 mL would be needed to titrate the sample, you must dilute it approximately 1: 2. Taking, for example, 25 mL of sample and making up to 50 mL.
Report sheet for Titration of vinegar Part I: Standardization of the NaOH solution with KHP Trial 1 Trial 2 Trial 3 Mass of Erlenmeyer flask + KHP (g) 78.34 78.27 78.01 Mass of empty flask (g) 77.12 77.12 77.12 Mass of KHP (g) 1.22 1.15 0.89 Final buret reading (mL) 31.35 30.53 27.71 Initial buret reading (mL) 16.35 15.78 14.20 Vol NaOH solution delivered (mL)…
A student performed three KHP titrations in Part 1 in order to standardize their NaOH solution. They reported the following measurements: Mass of KHP + Vial Mass of 'Empty' Vial Final Burette Reading Initial Burette Reading Determination #1 Determination #2 Determination #3 14.1992 g 14.0219 g 14.0982 g 13.3149 g 13.2301 g 13.2779 g 39.21 mL 0.49 mL 35.46 mL 0.86 mL 37.42 mL 1.59 mL How many moles of NaOH did they use in their third titration? Report your answer to the correct number of significant figures and only report the numerical value (no units).
Data for titration of 15.00 mL of vinegar with approximately 1.0 M NaOH. Note you must use the exact concentration of the standard NaOH solution to calculate the moles of NaOH. Quantity Еxample Trial 1 Trial 2 Trial 3 M NaOH (exact concentration) 0.992 M 0.953 M 0.953 M 0.953 M V initial buret reading = V, 0.20 mL 1.20 mL 0.52 mL 0.15 mL V final buret reading = V, 12.90 mL 14.22 mL 13.71 mL 13.31 mL %3D Vep = VNAOH added = V; - V, 12.70 mL 13.02 mL 13.19 mL 13.16 mL Vep = VNAOH in L 0.01270 L 0.01302 L 0.01319 L 0.01316 L moles NaOH = 0.0126 mol 0.0124 mol 0.0126 mol 0.0125 mol MNAOH X VNAOH moles AA = 0.0126 mol 0.0124 mol 0.0126 mol 0.0125 mol moles NaOH V sample = V acid 0.0150 L 0.0150 L 0.0150 L 0.0150 L (15.00 mL) (15.00 mL) (15.00 mL) Actual molarity 0.840 M 0.827 M 0.840 M 0.833 M of AA Average molarity for 3 trials => of AA 0.833 M 1. Report the acetic acid (AA) concentration of vinegar in units of molarity (M). 2. Use your average AA concentration to calculate the mass…
The Kjeldahl method was used to determine the nitrogen content of a protein. A 275 µL aliquot of a 47.0 mg/mL protein solution was digested in boiling sulfuric acid. The solution was made basic and the liberated NH, was collected in 5.00 mL of 0.0512 M HCl. A volume of 7.00 mL of 0.0174 M NaOH was required to react with the excess HCl. Calculate the weight percent of nitrogen in the protein. weight percent: wt% N
11. A 100.00 mL sample of orange juice, which has been fortified with calcium is titrated with 0.02357 M EDTA in the same method as this experiment. The initial buret reading is 0.15 mL and the final buret reading is 15.23 mL. How many mg of calcium are contained in the orange juice sample? Show your work. 12. What is the molarity of calcium in the orange juice sample from the above ques- tion? Show your work.
Dilute the stock solution: Using the solutions in the burets, carefully measure the following quantities of Co(NO3)2 solution and water into 5 large test tubes, to a total of 5.00 mL in each test tube. Yes, the optional video says to make 10.00 mL total, but 5.00 mL is sufficient at this time and generates less waste. Use the buret to measure the cobalt solution and the water. Test tube No. 1 2 3 4 5 mL Co2+ Soln 1.00 2.00 3.00 4.00 5.00 mL H2O 4.00 3.00 2.00 1.00 0.00 Total mL 5.00 5.00 5.00 5.00 5.00 Mix each test tube thoroughly: hold the top of the tube and mix the bottom well. Transfer a portion of each diluted sample into a clean, dry sample cuvette. fill the concentration table and do calculations please
Please show all the calculations. I have these information available: 32.00 mL of 1 butanol and 20.00 mL glacial acetic acid were in the 100 mL distilling flask. Initial Aliquot:1 mL and add around 20 mL of water.Volume of NaoH required for titration: 67.3 mL After Aliquot:1 mL and add around 20 mL of water.Volume of NaOH required for titration: 23.4 mL Concentration of NaOH: 0.0972 M
Based on the following SAMPLE 2 data, calculate the concentration (M) of NaOH. Report answer with FOUR decimal places. Do not include units in response. REPORT FOR EXPERIMENT 22 Neutralization-Titration I Data Table Sample 1 Sample 2 Mass of flask and KHP 94.7994 g 95.3800 g Mass of empty flask 93.6616 g 94.2144g Mass of KHP Final buret reading 18.25 mL 36.94 mL Initial buret reading 0.15 mL 18.24 mL Volume of base used