ang acid exactly Cinally g. What equation can you use in the "buffer region" of any acid/base reaction to solve for pH quickly? [HAJ h. Suppose a separate mixture is created that has a starting concentration of 0.20 M HA and 0.30 M KOH. What is the pH of the mixture after the components react? (Hint: [HA] > [OH-]) (PS - If you haven't watched the AP Classroom video on topics 8.4 and 8.5) i. Suppose a separate mixture is created that has a starting concentration of 0.20 M HA and 0.20 M KOH. What is the pH of the mixture after the components react? (Hint: [HA] = [OH-]) j. Suppose a separate mixture is created that has a starting concentration of 0.20 M HA and 0.10 M KOH. What is the pH of the mixture after the components react? (Hint: [HA] <[OH-])
ang acid exactly Cinally g. What equation can you use in the "buffer region" of any acid/base reaction to solve for pH quickly? [HAJ h. Suppose a separate mixture is created that has a starting concentration of 0.20 M HA and 0.30 M KOH. What is the pH of the mixture after the components react? (Hint: [HA] > [OH-]) (PS - If you haven't watched the AP Classroom video on topics 8.4 and 8.5) i. Suppose a separate mixture is created that has a starting concentration of 0.20 M HA and 0.20 M KOH. What is the pH of the mixture after the components react? (Hint: [HA] = [OH-]) j. Suppose a separate mixture is created that has a starting concentration of 0.20 M HA and 0.10 M KOH. What is the pH of the mixture after the components react? (Hint: [HA] <[OH-])
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
Can you please help me with H through J? (I have also included A through G if that info is needed). Thank you!
![ang acid
exactly
Einally
What equation can you use in the "buffer region'" of any acid/base reaction to solve for pH
quickly?
g.
pH= DKatlog1o
[HAJ
h. Suppose a separate mixture is created that has a starting concentration of 0.20 M HA and 0.30 M
KOH. What is the pH of the mixture after the components react? (Hint: [HA] > [OH-])
(PS - If you haven't watched the AP Classroom video on topics 8.4 and 8.5)
i. Suppose a separate mixture is created that has a starting concentration of 0.20 M HA and 0.20 M
KOH. What is the pH of the mixture after the components react? (Hint: [HA] = [OH-])
j. Suppose a separate mixture is created that has a starting concentration of 0.20 M HA and 0.10 M
KOH. What is the pH of the mixture after the components react? (Hint: [HA] <[OH-])](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F310fa1be-a638-47b3-9316-1b971054d314%2F09ddf5ed-4572-4441-87d5-71ea688bf367%2F6bj055_processed.jpeg&w=3840&q=75)
Transcribed Image Text:ang acid
exactly
Einally
What equation can you use in the "buffer region'" of any acid/base reaction to solve for pH
quickly?
g.
pH= DKatlog1o
[HAJ
h. Suppose a separate mixture is created that has a starting concentration of 0.20 M HA and 0.30 M
KOH. What is the pH of the mixture after the components react? (Hint: [HA] > [OH-])
(PS - If you haven't watched the AP Classroom video on topics 8.4 and 8.5)
i. Suppose a separate mixture is created that has a starting concentration of 0.20 M HA and 0.20 M
KOH. What is the pH of the mixture after the components react? (Hint: [HA] = [OH-])
j. Suppose a separate mixture is created that has a starting concentration of 0.20 M HA and 0.10 M
KOH. What is the pH of the mixture after the components react? (Hint: [HA] <[OH-])
![Use the diagram below to answer all parts of question 2:
12
(E)
11
10+
9+
8+
7+
E 6+
5-
4(A)
nalf equivalence
POInt
(В)
3
2
1
0.
50
100
Volume 0.1000 M KOH Added (mL)
2.
Answer the following questions that follow.
The titration curve above was created using [strong: weak] acid, HA. How do you know?
a.
The equivalence point is mone then t, thenefore it
is lar that the urve is of weak acid + strong base.
b. Based on part (a), write the net ionic equation for this reaction:
HA+KOH-ETA+ H20
c. What is pH of this titration at the equivalence point? 8.5
d. How many mL were needed to reach the half-equivalence point? Label this point on the graph.
What is the pH at that point?
60 mL wene nee ded + he PH is 5,5.
the half eaulvalene point is alhieved when half of the
e. What is the pKa of this acid, HA? Which point tells you? acid is bei ng neutralized lby
a half equvalence point, pH=Pka
SO, pH of pointB ISX 5.5, thenefone the pK.
f. Which part of the curve represents the "buffer region". What is happening there, with respect to
the ions present.
the base.
バから、6.
pegion A to B is the buffer negion.
in the
negion,
in pH due to the addinon of beye,
buffer
thene IS 1 Hhe change](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F310fa1be-a638-47b3-9316-1b971054d314%2F09ddf5ed-4572-4441-87d5-71ea688bf367%2F3jeinrs_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Use the diagram below to answer all parts of question 2:
12
(E)
11
10+
9+
8+
7+
E 6+
5-
4(A)
nalf equivalence
POInt
(В)
3
2
1
0.
50
100
Volume 0.1000 M KOH Added (mL)
2.
Answer the following questions that follow.
The titration curve above was created using [strong: weak] acid, HA. How do you know?
a.
The equivalence point is mone then t, thenefore it
is lar that the urve is of weak acid + strong base.
b. Based on part (a), write the net ionic equation for this reaction:
HA+KOH-ETA+ H20
c. What is pH of this titration at the equivalence point? 8.5
d. How many mL were needed to reach the half-equivalence point? Label this point on the graph.
What is the pH at that point?
60 mL wene nee ded + he PH is 5,5.
the half eaulvalene point is alhieved when half of the
e. What is the pKa of this acid, HA? Which point tells you? acid is bei ng neutralized lby
a half equvalence point, pH=Pka
SO, pH of pointB ISX 5.5, thenefone the pK.
f. Which part of the curve represents the "buffer region". What is happening there, with respect to
the ions present.
the base.
バから、6.
pegion A to B is the buffer negion.
in the
negion,
in pH due to the addinon of beye,
buffer
thene IS 1 Hhe change
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