Figure 11-7 A. 1) K*-0² Bu B. 1) Toll C. BH 1 H Br 1) H₂ 504 (cone) 2) H₂0, H + 2) Oct 3 2) K+ - 0² Bu 2) BH 3 + enantiomer 3) Hg(0Ac)₂, H₂O, H+ 3) OH- 4) Na BH4 3) H₂O₂, OH¯, H₂O
Figure 11-7 A. 1) K*-0² Bu B. 1) Toll C. BH 1 H Br 1) H₂ 504 (cone) 2) H₂0, H + 2) Oct 3 2) K+ - 0² Bu 2) BH 3 + enantiomer 3) Hg(0Ac)₂, H₂O, H+ 3) OH- 4) Na BH4 3) H₂O₂, OH¯, H₂O
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Transcribed Image Text:### Question
Which of the reaction sequences shown would accomplish the transformation shown in Figure 11-7?
### Answer Choices
- ○ A
- ○ B
- ○ C
- ○ D
---
### Explanation
This question requires students to identify the correct sequence of chemical reactions that would achieve a specific transformation. Since Figure 11-7 is mentioned but not visible in the question, students must refer to it and select the appropriate choice. Each option, labeled A through D, represents a possible reaction pathway.

Transcribed Image Text:**Figure 11-7:**
The image displays a chemical reaction scheme involving a bicyclic compound with an alcohol (-OH) group. The scheme illustrates different sequences of reagents that can be used to achieve the transformation of the starting compound into a product, along with its enantiomer.
**Reagents and Pathways:**
**Pathway A:**
1. \( \text{K}^+ - \text{O}^{t}\text{Bu} \)
2. \( \text{H}_2\text{O}, \text{H}^+ \)
**Pathway B:**
1. \( \text{TsCl} \)
2. \( \bigcirc\hspace{-4pt}-\hspace{-3pt}\bigcirc \text{Cl}_2\) (symbol for dichlorocyclopropane)
3. \( \text{Hg(OAc)}_2, \text{H}_2\text{O}, \text{H}^+ \)
4. \( \text{NaBH}_4 \)
**Pathway C:**
1. \( \text{HBr} \)
2. \( \text{K}^+ - \text{O}^{t}\text{Bu} \)
3. \( \text{OH}^- \)
**Pathway D:**
1. \( \text{H}_2\text{SO}_4 \) (conc)
2. \( \text{BH}_3 \)
3. \( \text{H}_2\text{O}_2, \text{OH}^-, \text{H}_2\text{O} \)
The end product is shown with an -OH group in a different stereochemical configuration, indicating the formation of an enantiomer. This reaction illustrates the complexity of stereochemical outcomes in organic synthesis and the significance of choosing appropriate reagents to achieve desired chirality.
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