EXPERIMENT Determination of Molecular weight: Approximately 0.3 grams of unknown acid is dissolved in 70.0 mL deionized water. The unknown acid solution is then titrated with 0.123 M NaOH (aq). • Initial volume of NaOH in the burette = 50 mL • Final volume of NaOH in the burette = 32 mL • Volume of NaOH used to complete the titration = • Number of moles of NaOH added= 13 135.50 g/mol • Number of moles of unknown acid present = MOLECULAR WEIGHT OF UNKNOWN ACID = Determination of pKa of the weak acid: 9,93

EXPERIMENT Determination of Molecular weight: Approximately 0.3 grams of unknown acid is dissolved in 70.0 mL deionized water. The unknown acid solution is then titrated with 0.123 M NaOH (aq). • Initial volume of NaOH in the burette = 50 mL • Final volume of NaOH in the burette = 32 mL • Volume of NaOH used to complete the titration = • Number of moles of NaOH added= 13 135.50 g/mol • Number of moles of unknown acid present = MOLECULAR WEIGHT OF UNKNOWN ACID = Determination of pKa of the weak acid: 9,93

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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