O,4335 m moles HCI 4.335m =0.4335m 10.00ML molarity of HCI

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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How to get the moles and molarity?
Part C. Determination of Unknown
Balanced chemical equation:
Hcl + Na OH -o Nacl t Hg0
Unknown number NA
Trial 1
Trial 2
Trial 3
Volume of unknown HCl
titrated
10.00mL
NA
NA
Initial burette reading
0.90mL
Final burette reading
30.90mL
Volume NaOH added
20 00ML
50.00mLXO.144 m=43.2m
moles NaOH added
4.335m
(Use average molarity from part B
and multiply it by the volume you added)
04335 m
moles HCl
4.335m
04335m
10.00 mL
molarity of HCl
Actual Molarity (from instructor)
0.3150M
percentage error
Transcribed Image Text:Part C. Determination of Unknown Balanced chemical equation: Hcl + Na OH -o Nacl t Hg0 Unknown number NA Trial 1 Trial 2 Trial 3 Volume of unknown HCl titrated 10.00mL NA NA Initial burette reading 0.90mL Final burette reading 30.90mL Volume NaOH added 20 00ML 50.00mLXO.144 m=43.2m moles NaOH added 4.335m (Use average molarity from part B and multiply it by the volume you added) 04335 m moles HCl 4.335m 04335m 10.00 mL molarity of HCl Actual Molarity (from instructor) 0.3150M percentage error
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