Calculate the change in pH that occurs when 1.10mmol of a strong acid is added to 100. mL of thesolutions listed below.Ka (CH3 CH₂ COOH) = 1.34 × 10-5.a. 0.0630 M CH3 CH₂COOH + 0.0630 MCH,CH,COONa.Change in pH =b. 0.630 M CH3 CH₂COOH + 0.630 MCH,CH,COONa.Change in pH =

Given that- Moles of acid = 1.10 mmol =0.0011 mol Acid dissociation constant of CH3CH2COOH, Ka= 1.34…

Answered: Calculate the change in pH that occurs…

Introduction to Chemical Engineering Thermodynamics

8th Edition

ISBN:9781259696527

Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart

Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart

Chapter1: Introduction

Section: Chapter Questions

Problem 1.1P

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Calculate the change in pH that occurs when 1.10 mmol of a strong acid is added to 100. mL of the solutions listed below. Ka (CH3 CH₂COOH) = 1.34 x 10-5. a. 0.0630 M CH3 CH₂ COOH + 0.0630 M CH3CH2COONa. Change in pH b. 0.630 M CH3 CH₂ COOH + 0.630 M CH3CH2COONa.