1. Calculate: 1. (273.15 K) / (0 oC) =, 2. (1365.75 K) * (__ oC) = 0 oC 3. (498 K) / ( oC) = (-47.5 oC) 2. The record temperatures for Minnesota in the month of September are 31°F and 91°F. What is the temperature difference in Kelvin?
1. Calculate: 1. (273.15 K) / (0 oC) =, 2. (1365.75 K) * (__ oC) = 0 oC 3. (498 K) / ( oC) = (-47.5 oC) 2. The record temperatures for Minnesota in the month of September are 31°F and 91°F. What is the temperature difference in Kelvin?
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Question
![1. Calculate:
1. (273.15 K) / (0 oC) =
2. (1365.75 K) * (_ oC) = 0 oC
3. (498 K) / (_ oC) = (-47.5 oC)
2. The record temperatures for Minnesota in the month
of September are 31°F and 91°F. What is the
temperature difference in Kelvin?
oC
%3D](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2ba0aec5-65e2-43b8-bb6a-70de8eae6b73%2F065a992d-df79-4cb3-9d1e-91c9964e3b89%2Fgu72vep_processed.jpeg&w=3840&q=75)
Transcribed Image Text:1. Calculate:
1. (273.15 K) / (0 oC) =
2. (1365.75 K) * (_ oC) = 0 oC
3. (498 K) / (_ oC) = (-47.5 oC)
2. The record temperatures for Minnesota in the month
of September are 31°F and 91°F. What is the
temperature difference in Kelvin?
oC
%3D
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