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1. Calculate: 1. (273.15 K) / (0 oC) =, 2. (1365.75 K) * (__ oC) = 0 oC 3. (498 K) / ( oC) = (-47.5 oC) 2. The record temperatures for Minnesota in the month of September are 31°F and 91°F. What is the temperature difference in Kelvin?

1. Calculate: 1. (273.15 K) / (0 oC) =, 2. (1365.75 K) * (__ oC) = 0 oC 3. (498 K) / ( oC) = (-47.5 oC) 2. The record temperatures for Minnesota in the month of September are 31°F and 91°F. What is the temperature difference in Kelvin?

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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1. Calculate: 1. (273.15 K) / (0 oC) = 2. (1365.75 K) * (_ oC) = 0 oC 3. (498 K) / (_ oC) = (-47.5 oC) 2. The record temperatures for Minnesota in the month of September are 31°F and 91°F. What is the temperature difference in Kelvin? oC %3D
Transcribed Image Text:1. Calculate: 1. (273.15 K) / (0 oC) = 2. (1365.75 K) * (_ oC) = 0 oC 3. (498 K) / (_ oC) = (-47.5 oC) 2. The record temperatures for Minnesota in the month of September are 31°F and 91°F. What is the temperature difference in Kelvin? oC %3D
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