Calculate the binding energy (in MeV) of the last neutron in the 188O nucleus. (Hint: You should compare the mass of 188O with the mass of 178O plus the mass of the last neutron. The mass of 178O = 16.999131 u, whereas the mass of 188O = 17.999160 u.) MeV
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- Taking into account the recoil (kinetic energy) of the daughter nucleus, calculate the kinetic energy K(alpha) of the alpha particle in the following decay of a 238U nucleus at rest. 238U⟶234Th+alpha K(alpha) = ? MeVConsider the following decay: 232 U → 228 Th + a . 232 U has a mass of 232.0371562 u, 228 Th has a mass of 228.0287411 u, and a has a mass of 4.002603 u. 92 90 92 90 Determine the disintegration energy (Q-value) in MeV. Q = Determine the KE of the daughter in MeV. KED = Determine the KE of the a particle in MeV & as a factor of Q. KE, = KEa = Qx Determine the speed of the a particle in terms of c. For an a particle, E. = 3.727 GeV. [NOTE: G stands for giga- which means 109 & M stands for mega- which means 10°.] Valpha = XCCalculate the binding energy per mole of nucleons for sodium-23. Masses needed for this calculation are (in g/mol) H = 1.00783, n = 1.00867, and Na = 22.98977. (Na) = n kJ/mol nucleons
- 223 A Ra nucleus undergoes alpha decay according to the reaction 223 219 He. Determine the following. (Let the 88 Ra → 88 86 Rn + 223 Ra be 223.0185 u, the atomic mass of atomic mass of 219 Rn be 219.0095 u and the atomic mass of He be 4.0026 u.) 86 (a) Q value (in MeV) for the process (Enter your answer to at least two decimal places.) MeV (b) Kinetic energy (in MeV) of the alpha particle after the decay (Enter your answer to at least two decimal places.) MeV (c) Kinetic energy (in MeV) of the daughter nucleus after the decay MeVThe rest mass of a proton is 1.0072764666 u and that of a neutron is 1.0086649158 u. The "He nucleus weighs 4.002602 u. Calculate the total binding energy of the nucleus.A state-of-the-art proton decay experiment is expected to detect 44% of the proton decays in a body of water. Assuming protons have a lifetime of 1031 years, how many m3 of water would you need in order to see 2 decays per month? (Assume a "month" is one-twelfth of a year.)
- Find the Energy emitted in the Alpha Decay of 238U in MeV. m(238U) = 238.050784 m(234Th) = 234.0436 m(4He) = 4.002602What is the energy released in this nuclear reaction 79201 Au 80201Hg + -1°e? (The atomic mass of 201 Au is 200.971657 u and that of 201Hg is 200.970302 u) Ans MeVConsider the following decay: 232 U 92 a mass of 4.002603 u. 228 Th+ a. 232 U has a mass of 232.0371562 u, 228 Th has a mass of 228.0287411 u, and a has 90 92 90 A.) Determine the disintegration energy (Q-value) in MeV. Q= B.) Determine the KE of the daughter in MeV. KED= C.) Determine the KE of the a particle in MeV & as a factor of Q. KE= KE=Qx D.) Determine the speed of the particle in terms of c. For an a particle, E = 3.727 GeV. [NOTE: G stands for giga- which means 10º & M stands for mega- which means 106.] Vα = XC
- Calculate the binding energy (in MeV) of the last neutron in the 4320Ca nucleus. (Hint: You should compare the mass of 4320Ca with the mass of 4220Ca plus the mass of the last neutron. The mass of 4220Ca = 41.958622 u, whereas the mass of 4320Ca = 42.958770 u.) MeVUranium (protons = 92, neutrons = 146, atomic mass = 238.050788 u) decays via alpha decay to Thorium (protons = 90, neutrons = 144, atomic mass = 234.043601 u). What is the kinetic energy of the emitted alpha particle? (Hint: Any energy that is not locked up in rest energy of the product nuclei will go to kinetic energy in the alpha particle.) (Hint: the answer is 4.27 MeV)A new element has been created artificially. It is named Elementy McFacium. The most common isotope of McFacium has 153 protons and 277 neutrons. The mass of this isotope of the new element is 402,188.91 MeV/c^2. What is the total mass deficit for the nucleus? Hint: The new element is not made as an ion! Use the mass of hydrogen atoms instead of protons. (Answer in atomic mass units u)