What is the energy released in the alpha decay 234 of ŠU? The mass of 00 Th is 234.044 u, of 92 238 U 238.051 u, of He 4.0026 u and 1 u 92 931.5 Mev.
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Q: For the alpha decay 238U → 234Th + 4He, the mass values for 238U, 4He and 234Th are 238.0508u,…
A: Atomic mass of Uranium= 238.0508u Atomic mass of Thorium=234.0436u Atomic mass of Helium=4.0026u
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Q: Known the rest energy for (233,92 U) is E_u=233.039u, with 1u=931.5MeV. he rest energies for one…
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- The rest mass of a proton is 1.0072764666 u and that of a neutron is 1.0086649158 u. The "He nucleus weighs 4.002602 u. Calculate the total binding energy of the nucleus.Find the Energy emitted in the Alpha Decay of 238U in MeV. m(238U) = 238.050784 m(234Th) = 234.0436 m(4He) = 4.002602Answers to d and e please
- Consider the following decay: 232 U 92 a mass of 4.002603 u. 228 Th+ a. 232 U has a mass of 232.0371562 u, 228 Th has a mass of 228.0287411 u, and a has 90 92 90 A.) Determine the disintegration energy (Q-value) in MeV. Q= B.) Determine the KE of the daughter in MeV. KED= C.) Determine the KE of the a particle in MeV & as a factor of Q. KE= KE=Qx D.) Determine the speed of the particle in terms of c. For an a particle, E = 3.727 GeV. [NOTE: G stands for giga- which means 10º & M stands for mega- which means 106.] Vα = XCA nuclei has a mass of 6.51×10-27 kg. What is its mass in Mev/c²? 3.65x10³ Mev/c² 3.92 Mev/² 7.85x10³ Mev/c² Question 3 Is the following decay possible? 232Th (Z=90) 236µ (Z = 92) + a 000 It's impossible to tell No YesFind the mass energy released in the alpha decay of Ac-220. atomic mass of 220 Ac = 220.014763 u; 89 atomic mass of 216 Fr = 216.003198 u; 87 atomic mass of He = 4.002603 u; u = 931.5 MeV/c^2. (in MeV) OA: 0.898 OB: 1.302 OC: 1.888 OD: 2.738 OE: 3.971 OF: 5.757 OG: 8.348 OH: 12.105
- An atom of 239Pu decays into 235U and an alpha particle. How much energy (in MeV) is released due to the decay?Consider the following decay: 209 83 Bi->> 205 TI + α. 81 209 Bi has a mass of 208.9803987 u, 205 TI has a mass of 204.9744275 u, and a has a mass of 4.002603 u. 81 83 A.) Determine the disintegration energy (Q-value) in MeV. Q= B.) Determine the KE of the daughter in MeV. KED= C.) Determine the KE of the a particle in MeV & as a factor of Q. KE = KE=Qx D.) Determine the speed of the a particle in terms of c. For an a particle, E, = 3.727 GeV. [NOTE: G stands for giga- which means 109 &M stands for mega- which means 106.] XCWhat is the disintegration energy (in MeV) of the spontaneous decay: 116Nd → Ce + He -> 58 Knowing that: 19 mNd = 143.910087 u. mce = 139.905439 u. mHe = 4.002603 u and 1u = 1.67 x 10-27 Kg.
- The nucleus of a lithium atom is 3 ^ 7 Li and its mass is 7.0160 amu. Calculate the binding energy in MeV. The relevant masses are, for the neutron, 1.0087 amu, and the proton 1.0073 amu. 1 amu is equivalent to 931 MeVWe want to get an idea of the actual mass of 235U involved in powering a nuclear power plant. Assume that a single fission event releases 200 MeV of thermal energy. A 1,000 MWe electric power plant has a thermal power of approximately 3,000 MWth. What rate of fission reactions is required to produce this power? (Note: 1 eV = 1.6 × 10−19 J.) The reactor core consists of approximately 100 tonnes of UO2 (1 tonne = 1,000 kg), which is enriched in 235U to 4%. How many full-power years could the reactor operate if all of the 235U were to be fissioned? What factors prevent such complete depletion of the 235U from occurring? Under the 235U depletion scenario of part b, what mass of fission products and what mass of high-level wastes (HLW) would be produced?Consider the fission reaction 141 n + U -> 235, 92U syXe + 92 38Sr +3n The masses of the components are 235 235.04393 세 xe| 140.여 2678 92 5 91.911 038 n 1.00 866 U Find the energy released in MeV Use the editor to format your answer