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214Po undergoes alpha decay to become 21Pb. If the Q value of the reaction is 7.83 MeV, calculate the kinetic energy of the alpha particle released.

214Po undergoes alpha decay to become 21Pb. If the Q value of the reaction is 7.83 MeV, calculate the kinetic energy of the alpha particle released.

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214Po undergoes alpha decay to become 210Pb. If the Q value of the reaction is 7.83 MeV, calculate the kinetic energy of the alpha particle released.
Transcribed Image Text:214Po undergoes alpha decay to become 210Pb. If the Q value of the reaction is 7.83 MeV, calculate the kinetic energy of the alpha particle released.
Expert Solution
Concept and Principle:
  • When an unstable nucleus undergoes alpha decay they release a helium nucleus or alpha particle. This kind of decay is called alpha decay.

 

  • The following reaction takes place in alpha decay.

XNZA→X'N−2Z−2A−4+He224

Here X is the parent nucleus and X' is the daughter nucleus.

 

  • The kinetic energy of the alpha particle released is given by,

Kα=(A−4A)Q

Here A is the atomic number of the parent nucleus and Q is the energy released in the reaction.

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