7. according to the reaction: 238 234 4 U Th+ He 92 90 2 A uranium nucleus undergoes alpha decay Take the masses to be 234.043680 u for Th and 4.002603 u for He. The mass for the uranium nucleus is 238.050788 Find the difference in mass between the initial nucleus and the final products, in u. Then use 931 Mev/u to get your answer in energy units Mev. This is the nuclear energy released in the reaction and helps explain both fission and fusion nuclear reactions.
7. according to the reaction: 238 234 4 U Th+ He 92 90 2 A uranium nucleus undergoes alpha decay Take the masses to be 234.043680 u for Th and 4.002603 u for He. The mass for the uranium nucleus is 238.050788 Find the difference in mass between the initial nucleus and the final products, in u. Then use 931 Mev/u to get your answer in energy units Mev. This is the nuclear energy released in the reaction and helps explain both fission and fusion nuclear reactions.
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Transcribed Image Text:7.
according to the reaction:
238
234
4
U
Th+
He
92
90
2
A uranium nucleus undergoes alpha decay
Take the masses to be 234.043680 u for Th and 4.002603 u for He.
The mass for the uranium nucleus is 238.050788
Find the difference in mass between the initial nucleus and the final
products, in u. Then use 931 Mev/u to get your answer in energy units
Mev. This is the nuclear energy released in the reaction and
helps explain both fission and fusion nuclear reactions.
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