Calculate AGo' for the reactionNADH + pyruvate → NAD+ + lactateYou are given:Faradays constant F = 96.5 kJ/mol.VEo' : NAD+ / NADH = 0.320VEo' : Pyruvate/lactate = -0.185 VA.13 kJ/molВ.97 k j/molС.49 kJ/molD.26 k j/molЕ.None of the aboveB.

Electrons from NADH and a proton are used to reduce pyruvate into lactate in lactic acid…

Answered: Calculate AGo' for the reaction NADH +…

Biochemistry

9th Edition

ISBN:9781319114671

Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Chapter1: Biochemistry: An Evolving Science

Section: Chapter Questions

Problem 1P

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3.An enzyme catalyzed reaction is studied and the following kinetic analysis is obtained: |[S), mM 0.050 0.075 v, (µM min") 0.93 1.264 1.77 2.14 3.7 0.125 0.175 0.935 a. Using Excel, make a fully labeled Lineweaver-Burk plot and determine the Km and Vmax for the enzyme b. The reactions were set up dissolving 1 mg of the enzyme (MW= 100000 Da) in 100 ml of final reaction buffer. Determine the turnover number for the enzyme assuming 1 active site exists per enzyme molecule? c. Determine the catalytic efficiency for the enzyme d. The same reactions are performed in presence of an inhibitor A and the resulting velocities determined: v plus inhibitor, (µM min) 0.272 0.37 0.518 0.626 |1.08 |[S), mM 0.050 0.075 0.125 0.175 0.935 Plot these data on the same graph as above and determine the new Km and Vmax and the type of inhibitor (competitive, non-competitive). e. Can the effects of the inhibitor be over-ridden by adding more substrate? Why?
The table below provides kinetic information when ADH is reacted with ethanol alone, NAD+ alone, and ethanol with NAD+ For the experiment that reacted both ethanol and NAD+ with ADH, estimate Vmax and KM for ADH
Identify the enzymes in Table, whose catalytic effi ciencies are near the diff usion-controlled limit.
PTP1B Substrate kcat Km. kcat/Km UM 10-7 x (s-1 M) DADEPYLIPQQG DADAPYLIPQQG DAAEP YLIPQQG AAAAPYLIPQQG 44.6 + 1.8 39.8 + 0.32 3.9 + 0.9 13.7 + 0.46 1.1 + 0.25 0.29 + 0.01 35.3 + 0.22 6.6 + 0.22 0.53 + 0.02 34.7 + 0.25 52.7 + 0.7 0.066 + 0.001 ) The units for kcat/KM in the above are given according to standard scientific notation. On this (d) ( basis what is the value of this kinetic parameter for the DADEPYLIPQQG substrate?
I have a question, what are these ''a'' means in this plot? Normally its 1/vmax or -1/km. Please be specific. Thank you.
What is the Vmax of an enzyme at 1 μM with -4G RT k = 6.2x 10¹2 s-1 (Ideal gas constant R = 8.314 J K-1 mol-1) cat 0.14 μM S-1 1.4 µM s-1 14 μM s-1 0.14 mM s-1 1.4 mM s-1 activation energy (AG) of 55000 J/mol at 298K?
22. For the process, A B, Keq is 0.02 at 37°C. For the process, BC, Keq 1000 at 37°C. A. Determine Keq (AC), the equilibrium constant for the overall process A C, from Keq (AB) and Keq (BC). B. Determine standard-state free energy changes for all three processes and use AG'(AC) to determine Keq (AC). Make sure that this value agrees with that determined in part A of this problem.
Case Study: Enzyme Kinetics Data for new statin drug (inhibits HMG CoA reductase): ● ● I Substrate (UM) 0.5 1.0 1.5 2.5 3.5 || Rate of reaction (mm/min) 23.5 32.2 36.9 41.8 44 What are the Kms of the uninhibited and inhibited reactions? Rate of reaction in presence of 5.0 nM statin Using the above date, create a double-reciprocal (Lineweaver Burk) plot. What type of inhibition is shown by the new statin? What are the Vmax of the uninhibited and inhibited reactions? 16.67 25.25 30.49 37.04 38.91
can you explain what is happening in the attached graph? Figure 3: Lineweaver-Burke plot of alkaline phosphatase activity without inhibitor
2. The Km of a particular enzyme is 2.0 x 105 M. If the initial velocity (Vo) is 0.16 mmol/min for [S] = 0.15 M, what will be the initial velocity when [S] =2.0 x 10+M?
2.3
Please answer asap and in short

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Calculate AGo' for the reaction NADH + pyruvate → NAD+ + lactate You are given: Faradays constant F = 96.5 kJ/mol.V %3D Eo' : NAD+ / NADH = 0.320V Eo': Pyruvate/lactate = -0.185 V А. 13 kJ/mol В. 97 k j/mol С. 49 kJ/mol D. 26 k j/mol Е. None of the above