c) The overall rate law can be posed as:   −d[RCOOR′]dt=k[RCOOR′]n[OH−]m What is the overall rate constant, k, for the reaction? (include appropriate units) k =

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Hello i have the answers for part a and b but i dont know how to find part c (overall rate constant)

a) Consider the base hydrolysis of an ester.
RCOOR' + OH → RCOO + R'OH     (where R and R' represent organic groups).

The kinetics of this reaction, for a particular ester, were studied using the isolation method.

When [OH] >> [RCOOR'] a pseudo-rate law can be posed:

  −d[RCOOR′]dt=k′[RCOOR′]n
With initial concentrations:
  [OH]0 = 0.900 M
  [RCOOR']0 = 0.0010 M,
  a plot of ln[RCOOR'] versus t gave a straight line with slope = -71.5 s-1 and y-intercept = -6.91.
 order n = 1 and k' = 71.5 /s

     


b) When [OH] << [RCOOR'] a pseudo-rate law can be posed:

  −d[OH−]dt=k′′[OH−]m
With initial concentrations:
  [OH]0 = 0.0015 M
  [RCOOR']0 = 0.600 M
  a plot of ln[OH-] versus t gave a straight line with slope = -47.7 s-1 and y-intercept = -6.50.
order m 1 and k'' = 47.7 /s

c) The overall rate law can be posed as:

  −d[RCOOR′]dt=k[RCOOR′]n[OH−]m

What is the overall rate constant, k, for the reaction? (include appropriate units)
k = 

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