enus equation The rate constant of a certain reaction is known to obey the Arrhenius equation, and to have an activation energy E=45.0 kJ/mol. If the rate constant of this reaction is 1.2 x 106 M1. 1 at 328.0 °C, what will the rate constant be at 293.0 °C? Round your answer to 2 significant digits. -1 k = M¹ s¹ db X S ? A
enus equation The rate constant of a certain reaction is known to obey the Arrhenius equation, and to have an activation energy E=45.0 kJ/mol. If the rate constant of this reaction is 1.2 x 106 M1. 1 at 328.0 °C, what will the rate constant be at 293.0 °C? Round your answer to 2 significant digits. -1 k = M¹ s¹ db X S ? A
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Using the Arrhenius Equation to Calculate \( k \) at One Temperature**
### Problem Statement:
The rate constant of a certain reaction is known to obey the Arrhenius equation, and to have an activation energy \( E_a = 45.0 \) kJ/mol. If the rate constant of this reaction is \( 1.2 \times 10^6 \) M\(^{-1}\)s\(^{-1}\) at 328.0 °C, what will the rate constant be at 293.0 °C?
*Round your answer to 2 significant digits.*
### Given Data:
- \( k_1 = 1.2 \times 10^6 \) M\(^{-1}\)s\(^{-1}\)
- Temperature \( T_1 = 328.0 \) °C
- Temperature \( T_2 = 293.0 \) °C
- Activation Energy \( E_a = 45.0 \) kJ/mol
### Answer Box:
\[
k = [\Box] \, \text{M}^{-1}\text{s}^{-1}
\]
- Options for answer:
- X
- 5
- ?
**Note:** This problem requires the application of the Arrhenius equation to determine the rate constant at a different temperature. Use appropriate mathematical conversions and constants to find the solution.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Faf399169-ef14-4107-9621-c5ec1888471d%2F8f3c3480-1605-44eb-b611-1a4789dc5a90%2Fq37ipll_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Using the Arrhenius Equation to Calculate \( k \) at One Temperature**
### Problem Statement:
The rate constant of a certain reaction is known to obey the Arrhenius equation, and to have an activation energy \( E_a = 45.0 \) kJ/mol. If the rate constant of this reaction is \( 1.2 \times 10^6 \) M\(^{-1}\)s\(^{-1}\) at 328.0 °C, what will the rate constant be at 293.0 °C?
*Round your answer to 2 significant digits.*
### Given Data:
- \( k_1 = 1.2 \times 10^6 \) M\(^{-1}\)s\(^{-1}\)
- Temperature \( T_1 = 328.0 \) °C
- Temperature \( T_2 = 293.0 \) °C
- Activation Energy \( E_a = 45.0 \) kJ/mol
### Answer Box:
\[
k = [\Box] \, \text{M}^{-1}\text{s}^{-1}
\]
- Options for answer:
- X
- 5
- ?
**Note:** This problem requires the application of the Arrhenius equation to determine the rate constant at a different temperature. Use appropriate mathematical conversions and constants to find the solution.
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