The second-order rate constant for the decomposition of nitrous oxide to nitrogen molecules and oxygen atoms has been determined at various temperatures: Determine the activation energy graphically. Go k(M1·s)| T(°C) 1.87 × 10-3| 600 0.0113 650 0.0569 700 0.244 750 x 10 kJ/mol (Enter your answer in scientific notation.)
The second-order rate constant for the decomposition of nitrous oxide to nitrogen molecules and oxygen atoms has been determined at various temperatures: Determine the activation energy graphically. Go k(M1·s)| T(°C) 1.87 × 10-3| 600 0.0113 650 0.0569 700 0.244 750 x 10 kJ/mol (Enter your answer in scientific notation.)
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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![Be sure to answer all parts.
The second-order rate constant for the decomposition of nitrous oxide to nitrogen molecules and oxygen
atoms has been determined at various temperatures:
Determine the activation energy graphically.
Gr
k(M'·s) | T(°C)
1.87 × 10 3 600
0.0113
650
0.0569
700
0.244
750
× 10
kJ/mol
(Enter your answer in scientific notation.)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc076a9b0-0448-4725-9806-e2628b347801%2F30ff3e48-b8f2-4f77-ba41-005617df231c%2Fxphwby_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Be sure to answer all parts.
The second-order rate constant for the decomposition of nitrous oxide to nitrogen molecules and oxygen
atoms has been determined at various temperatures:
Determine the activation energy graphically.
Gr
k(M'·s) | T(°C)
1.87 × 10 3 600
0.0113
650
0.0569
700
0.244
750
× 10
kJ/mol
(Enter your answer in scientific notation.)
Expert Solution
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Step
The rate constant with respect to temperature was explained by Arrhenius by using equation
lnK = (- Ea / RT) + lnA
Ea = activation energy kj / mol
R = 8.314 j/ mol k
A = pre exponential factor
K = rate constant
T = temperature in Kelvin
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