1) Write the general rate law equation for the reaction Acetone (C,H,0(a) + Haa) + lodine (1z(aq)) C,H;01(aq) + Hag)+ Tag)

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Chapter1: Chemical Foundations
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Complete the following exercises
1) Write the general rate law equation for the reaction
Acetone (C3H,0(aq)) + Hag) + Iodine (12(aq)
→ C3H501(aq) + Haq) + Taq)
Rate
K CAcetore J [ Lz)
2) Determine the value of the exponents. Write the complete ratio comparing one reaction
mixture to another and show the cancellation of terms. Remember to compare the rates
for two mixtures for which only one of the concentrations varies.
a)
Rate I_= 1.9x10" M/s= k [IGM)" (020) [0.0010M)"
Rate „I = 38x106 M/s = K [o.8oM]o2079 Po.00/ DM]2
%3D
3.8x10-6
2.7089 =(66)*
%3D
%3D
log 2.0789. 1oq1-67% log[0807
0:3178 = x Co 300)
l0.80]x
0.3178
Exponent for Acetone, x =
1.1
3010
b)
To.4OM) (0.0010M)
C02OM)" 10.0010M)
lo4oM)-y log Lozom)
Rate = 8-0 Y[O
M/s= k(o.80
)
%3D
%3D
Rate I= 3.4ylo-t M/s= Rlo.60)^
%3D
log 2-1053 = ylog (ouoy log Lozom)
O-20m)
y=o.3237
l107
Exponent for H", y =
0.3010
c)
6.
2.
Rate I =
3.8x10 M/s= k Co8oM)" L020M)
%3D
k Coi8o Mje Co 20)y coo00Sm)
log (0.0010M)- log (o.000sm)
=2 (0-3010)
Rate
%3D
4.0x10~ M/=
(० ५ ०-११
0.0223
-0.07
0.0223
Exponent for I2, z =-0.07
0:3010
Transcribed Image Text:Complete the following exercises 1) Write the general rate law equation for the reaction Acetone (C3H,0(aq)) + Hag) + Iodine (12(aq) → C3H501(aq) + Haq) + Taq) Rate K CAcetore J [ Lz) 2) Determine the value of the exponents. Write the complete ratio comparing one reaction mixture to another and show the cancellation of terms. Remember to compare the rates for two mixtures for which only one of the concentrations varies. a) Rate I_= 1.9x10" M/s= k [IGM)" (020) [0.0010M)" Rate „I = 38x106 M/s = K [o.8oM]o2079 Po.00/ DM]2 %3D 3.8x10-6 2.7089 =(66)* %3D %3D log 2.0789. 1oq1-67% log[0807 0:3178 = x Co 300) l0.80]x 0.3178 Exponent for Acetone, x = 1.1 3010 b) To.4OM) (0.0010M) C02OM)" 10.0010M) lo4oM)-y log Lozom) Rate = 8-0 Y[O M/s= k(o.80 ) %3D %3D Rate I= 3.4ylo-t M/s= Rlo.60)^ %3D log 2-1053 = ylog (ouoy log Lozom) O-20m) y=o.3237 l107 Exponent for H", y = 0.3010 c) 6. 2. Rate I = 3.8x10 M/s= k Co8oM)" L020M) %3D k Coi8o Mje Co 20)y coo00Sm) log (0.0010M)- log (o.000sm) =2 (0-3010) Rate %3D 4.0x10~ M/= (० ५ ०-११ 0.0223 -0.07 0.0223 Exponent for I2, z =-0.07 0:3010
3) Complete the rate law equation by substituting the values of the exponents x, y and z in
the four equations. Determine the value ofk for each reaction mixture. Show your work
and give the correct units for k.
-2
2.4x10
Mixture I: k =
3,8y10-6
2-4
0.80X0-20 x 0-00/0
9.9x10
-6
Mixture II: k =
=2.5
1-6x020x0-06 10
Mixture III: k=
?ox10-6
20 x 10
= 2-5
6.80x0 Y0 Ao.
S xio-
-6
Mixture IV: k=
X10
4.0x10
0.80 x0.20x0.00
ニ
3.
)
Average k =
%3D
4) Write the complete rate law by substituting the values of x, y, z and k into the general rate
law.
5) What is the overall order of the reaction?
Transcribed Image Text:3) Complete the rate law equation by substituting the values of the exponents x, y and z in the four equations. Determine the value ofk for each reaction mixture. Show your work and give the correct units for k. -2 2.4x10 Mixture I: k = 3,8y10-6 2-4 0.80X0-20 x 0-00/0 9.9x10 -6 Mixture II: k = =2.5 1-6x020x0-06 10 Mixture III: k= ?ox10-6 20 x 10 = 2-5 6.80x0 Y0 Ao. S xio- -6 Mixture IV: k= X10 4.0x10 0.80 x0.20x0.00 ニ 3. ) Average k = %3D 4) Write the complete rate law by substituting the values of x, y, z and k into the general rate law. 5) What is the overall order of the reaction?
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