Breast feeding sometimes results in a temporary loss of bone mass as calcium is depleted in the mother's body to provide for milk production. An investigation gave the following data on total body bone mineral content (g) for a sample of mothers both during breast feeding (B) and in the postweaning period (P).Subject12345678910B2170184025632348272126012386264025491852P2300199425942523285227742534282925782039Do the data suggest that true average total body bone mineral content during postweaning exceeds that during breast feeding by more than 25 g? State and test the appropriate hypotheses using a significance level of 0.05. (Use a statistical computer package to calculate the P-value. Use ?P − ?B. Round your test statistic to two decimal places and your P-value to three decimal places.)t= df= P-value= ConclusionFail to reject H0. OR Reject H0.

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Description: Breast feeding sometimes results in a temporary loss of bone mass as calcium is depleted in the mother's body to provide for milk production. An investigation gave the following data on total body bone mineral content (g) for a sample of mothers both

We use the paired t-test for the given problem, where μd = μP – μB The test hypothesis are, H0: μd =…

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MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Breast feeding sometimes results in a temporary loss of bone mass as calcium is depleted in the mother's body to provide for milk production. An investigation gave the following data on total body bone mineral content (g) for a sample of mothers both during breast feeding (B) and in the postweaning period (P).

Subject	1	2	3	4	5	6	7	8	9	10
B	2170	1840	2563	2348	2721	2601	2386	2640	2549	1852
P	2300	1994	2594	2523	2852	2774	2534	2829	2578	2039

Do the data suggest that true average total body bone mineral content during postweaning exceeds that during breast feeding by more than 25 g? State and test the appropriate hypotheses using a significance level of 0.05. (Use a statistical computer package to calculate the P-value. Use ?_P − ?_B. Round your test statistic to two decimal places and your P-value to three decimal places.)

t	=
df	=
P-value	=

Conclusion

Fail to reject H₀. OR Reject H₀.

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