5.2 4.5 5.9 6.0 6.7 5.8 6.6 8.1 6.0 7.4 5.9 5.5 5.8 4.8 6.3 4.9 6.0 5.2 8.4 6.1 7.8 7.1 5.5 7.2 suggest that at least two of the grains differ with respect to true average thiamin content? Use a level α = 0.05 test. priate hypotheses. Н2 #Из #На ast two μ's are equal H₂=H3 = H4 ast two μ's are unequal H₂H₂ = 14.
5.2 4.5 5.9 6.0 6.7 5.8 6.6 8.1 6.0 7.4 5.9 5.5 5.8 4.8 6.3 4.9 6.0 5.2 8.4 6.1 7.8 7.1 5.5 7.2 suggest that at least two of the grains differ with respect to true average thiamin content? Use a level α = 0.05 test. priate hypotheses. Н2 #Из #На ast two μ's are equal H₂=H3 = H4 ast two μ's are unequal H₂H₂ = 14.
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
Related questions
Question
amit
pleasedo not uplod hand writting photo
Transcribed Image Text:Six samples of each of four types of cereal grain grown in a certain region were analyzed to determine thiamin content, resulting in the following data (µg/g).
Wheat 5.2 4.5 5.9 6.0 6.7 5.8
Barley 6.6 8.1 6.0 7.4 5.9 5.5
Maize 5.8 4.8 6.3 4.9 6.0 5.2
8.4 6.1 7.8 7.1 5.5 7.2
Oats
Does this data suggest that at least two of the grains differ with respect to true average thiamin content? Use a level a = 0.05 test.
State the appropriate hypotheses.
O Ho: M₁ M₂ M3 ‡ M4
#
: at least two μ's are equ
Ha:
о но: M1=M2=Nз =Ма
Ha: at least two μ's are unequal
о но: M1=M2=Nз =Ма
: all four 's are unequal
Ha:
O Ho: M₁ M₂
#
#
M3 M4
#
H₂: all four μ's are equal
Compute the test statistic value. (Round your answer to two decimal places.)
f =
What can be said about the P-value for the test?
O P-value > 0.100
0.050 < P-value < 0.100
0.010 P-value < 0.050
0.001 P-value < 0.010
O P-value < 0.001
State the conclusion in the problem context.
Fail to reject Ho. There is not significant evidence that at least two of the grains differ in average thiamin content.
Reject Ho. There is not significant evidence that at least two of the grains differ in average thiamin content.
Reject Ho. There is significant evidence that at least two of the grains differ in average thiamin content.
Fail to reject Ho. There is significant evidence that at least two of the grains differ in average thiamin content.
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