Based on question 4, calculate hmax forv=10m/s.hm(10)hm(v=10);Based on question 4, find the critical speed forhmax =0fzeros(hm,6)roots ([1/(2*g),g*D^2/2,-H];fzero(hm,6);zeros(hm, 6); A projectile is fired towards a wall of height Hfrom a distance D with speed v and angle eto the horizontal. The angle e is chosen tomaximize the height, hmax, of the projectilegD²2v2v22gabove the wall. h maxH,--where g=9.81m/s2 , D=2m and H=2m.D=2; H=2; g=9.81;hm=@(v) (v.^2)/(2*g)-(g*D^2)/(2*v.^2)-H;D=2; H=2; g=9.81;hm=@(v) (v.^2)/(2*g)-(g*D^2)/2*v.^2)-H;

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Answered: Based on question 4, calculate hmax for…

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Based on question 4, calculate hmax for v=10m/s. hm(10) hm(v=10); Based on question 4, find the critical speed for hmax =0 fzeros(hm,6) roots ([1/(2*g),g*D^2/2,-H]; fzero(hm,6); zeros(hm, 6);

Based on question 4, calculate hmax for v=10m/s. hm(10) hm(v=10); Based on question 4, find the critical speed for hmax =0 fzeros(hm,6) roots ([1/(2g),gD^2/2,-H]; fzero(hm,6); zeros(hm, 6);