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Based on question 4, calculate hmax for v=10m/s. hm(10) hm(v=10); Based on question 4, find the critical speed for hmax =0 fzeros(hm,6) roots ([1/(2*g),g*D^2/2,-H]; fzero(hm,6); zeros(hm, 6);

Based on question 4, calculate hmax for v=10m/s. hm(10) hm(v=10); Based on question 4, find the critical speed for hmax =0 fzeros(hm,6) roots ([1/(2*g),g*D^2/2,-H]; fzero(hm,6); zeros(hm, 6);

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Based on question 4, calculate hmax for v=10m/s. hm(10) hm(v=10); Based on question 4, find the critical speed for hmax =0 fzeros(hm,6) roots ([1/(2*g),g*D^2/2,-H]; fzero(hm,6); zeros(hm, 6);
Transcribed Image Text:Based on question 4, calculate hmax for v=10m/s. hm(10) hm(v=10); Based on question 4, find the critical speed for hmax =0 fzeros(hm,6) roots ([1/(2*g),g*D^2/2,-H]; fzero(hm,6); zeros(hm, 6);
A projectile is fired towards a wall of height H from a distance D with speed v and angle e to the horizontal. The angle e is chosen to maximize the height, hmax, of the projectile gD² 2v2 v2 2g above the wall. h max H, - - where g=9.81m/s2 , D=2m and H=2m. D=2; H=2; g=9.81; hm=@(v) (v.^2)/(2*g)-(g*D^2)/(2*v.^2)- H; D=2; H=2; g=9.81; hm=@(v) (v.^2)/(2*g)-(g*D^2)/2*v.^2)- H;
Transcribed Image Text:A projectile is fired towards a wall of height H from a distance D with speed v and angle e to the horizontal. The angle e is chosen to maximize the height, hmax, of the projectile gD² 2v2 v2 2g above the wall. h max H, - - where g=9.81m/s2 , D=2m and H=2m. D=2; H=2; g=9.81; hm=@(v) (v.^2)/(2*g)-(g*D^2)/(2*v.^2)- H; D=2; H=2; g=9.81; hm=@(v) (v.^2)/(2*g)-(g*D^2)/2*v.^2)- H;
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