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- I need to find the angle of projection for the maximum range. I have the following information: angle (degrees) and average range (cm). Here are two angles and the range for each. Angle Average Range (cm) 10 146.5 45 272.5 I think that I use this formula but I am not for sure. R=(V20 sin 2 theta)/g Can you help me figure this out so that I can do the rest of the angles and ranges.Let /be the line through the point with coordinates (0,1,0) in the direction of the vector their coordinates) lie on ?? a. (2,3,0) O b. (0, -1,0) O c. (1, 1, -1) O d. (1, 2,-1) 1 1 -1 Which of the following points (given byPls show full solution legibly, thank you!!
- Make g the subject in Ep=mxgxhQ2. Consider the following problem. (CLO3) (10 Marks)Maximize Z = x1 + 2x2,subject to-x1+x2<=-24x1 _+x2 <= 4andx1 >=0, x2 >=0.(a) Demonstrate graphically that this problem has no feasible solutions. (5 Marks)(b) Construct the dual problem. (5 Marks)B. Solve and graph the following problems. 1. You found a treasure map and it said: Start at the well, go 100m straight south, then 30m 40° north of west, then 25m straight east, and finally 45m, 75° south of east. Using the Polygon Method, how far from the well and in what direction is the hidden treasure?
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- VectorI is 20.00km southeast, Z is14.00km west,A is 12.50km 35degree W of S, and L is 15.00km 58degree N of W.If the resultant, R, is R=I+Z+A+L, (a) find the ?-component of ?, and (Ans: ?? = −14.98 km) (b) the ?-component of ?. (Ans: ?? = −11.66 km) (c) What is the magnitude of the resultant? (Ans: ? = 18.98 km) (d) At what angle and direction is the resultant pointing to? (θ = 37.90degree S of W)Find the magnitude of OB .ds for the closed path (a )shown in the figure: 05 A 1 A ® 2 A Select one: а. О b. 3μ. (Τ.m) O C. 4μ. (Τ.m) d. 1μ. (T.m)Kindly give me a detailed answer in a clear handwriting of subpart (b). I am attaching the full question but I only need (b). All the questions are related. I only have few minutes kindly give the ans ASAP. I will upvote if the answer is correct and answered soon. Thank you.