At time t, Orange's x-position is x(t) and Green's y-position is y(t). Orange and Greenfly at vo and vG The numbers (for this problem) are:x(0) = -55.7 metersy(0) = -157.3 meters• Vo = 14 m/s• VG = 10 m/st = 3.3 sHow far apart are they at time t?The numbers (for this problem) are:Vo = 15.3 m/s• VG = 11.5 m/sCalculate the magnitude of Orange's velocity relative to Green's (in m/s). drv(t) =dt%3DThis means that if At is sufficiently small and Ar is the displacement during At, wecan approximate Ar as v(t) At. (With r(t) given below, nothing prevents you from anexact calculation except the approximation of the numbers. But v(t) At may beeasier.)An object moves according to the following function of time. This problem will bepurely numerical, although if you wish, you may think of the numbers as numbers ofmeters, seconds, meters/second, and so forth.x(t)A + Bt2r(t) =%3D%3DCt + Dt3Calculate the distance the object moves during the time interval (t - At/2, t + At/2),at least approximately -- to within three percent. The numbers:• A = 7.9• B = 5.4• C = 2.2D = 8.9•t 8.8At = 0.048

Name: At time t, Orange's x-position is x(t) and Green's y-position is y(t)
Uploaded: 2024-03-05T11:56:34.000Z
Channel: Bartleby
Description: At time t, Orange's x-position is x(t) and Green's y-position is y(t). Orange and Greenfly at vo and vG The numbers (for this problem) are:x(0) = -55.7 metersy(0) = -157.3 meters• Vo = 14 m/s• VG = 10 m/st = 3.3 sHow far apart are they at time t?The