A particle moves with the following trajectory: x = 0.403[m/s*]•t“ - cos(1.07HZ-t) What is the instanteneous acceleration in the x direction at t = 43.5s? Answer: m/s^2 Om/s Oms^2
A particle moves with the following trajectory: x = 0.403[m/s*]•t“ - cos(1.07HZ-t) What is the instanteneous acceleration in the x direction at t = 43.5s? Answer: m/s^2 Om/s Oms^2
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![A particle moves with the following trajectory:
x = 0.403[m/s*]•t - cos(1.07HZ-t)
What is the instanteneous acceleration in the x direction at t = 43.5s?
Answer:
m/s^2 Om/s Oms^2](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2ef31c9f-1e44-437f-a71e-09574dc73129%2F15cb3f16-5ebf-4d3c-83fa-8e06c2c273bb%2F8on7tsg_processed.png&w=3840&q=75)
Transcribed Image Text:A particle moves with the following trajectory:
x = 0.403[m/s*]•t - cos(1.07HZ-t)
What is the instanteneous acceleration in the x direction at t = 43.5s?
Answer:
m/s^2 Om/s Oms^2
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