A particle is traveling in two-dimensional motion as follows: x(t)=(35t4-500t3 + 50t) m y(t)= (38t3 -48t2 -20) m where t is in seconds and x,y in meters Determine: The velocity and acceleration of the particle after 5 seconds The average velocity of the particle between 0 and 5 seconds Is the particle accelerating or decelerating at 5 seconds? Is the acceleration constant?
Displacement, Velocity and Acceleration
In classical mechanics, kinematics deals with the motion of a particle. It deals only with the position, velocity, acceleration, and displacement of a particle. It has no concern about the source of motion.
Linear Displacement
The term "displacement" refers to when something shifts away from its original "location," and "linear" refers to a straight line. As a result, “Linear Displacement” can be described as the movement of an object in a straight line along a single axis, for example, from side to side or up and down. Non-contact sensors such as LVDTs and other linear location sensors can calculate linear displacement. Non-contact sensors such as LVDTs and other linear location sensors can calculate linear displacement. Linear displacement is usually measured in millimeters or inches and may be positive or negative.
A particle is traveling in two-dimensional motion as follows:
x(t)=(35t4-500t3 + 50t) m
y(t)= (38t3 -48t2 -20) m where t is in seconds and x,y in meters
Determine:
- The velocity and acceleration of the particle after 5 seconds
- The average velocity of the particle between 0 and 5 seconds
- Is the particle accelerating or decelerating at 5 seconds?
- Is the acceleration constant?
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