### Velocity vs. Time Graph AnalysisThis graph illustrates the velocity of an object over time, measured in meters per second (m/s) on the y-axis and time in seconds (s) on the x-axis. The graph is segmented into several labeled sections: A, B, C, D, E, F, G, and H, representing different intervals of motion.#### Graph Description1. **Interval A (0s - 2s):** The object accelerates from -2 m/s to 0 m/s.2. **Interval B (2s - 4s):** The object accelerates from 0 m/s to 2 m/s.3. **Interval C (4s - 6s):** The object maintains a constant velocity of 4 m/s.4. **Interval D (6s - 8s):** The object decelerates from 4 m/s to 0 m/s.5. **Interval E (8s - 10s):** The object accelerates in the negative direction, reaching -2 m/s.6. **Interval F (10s - 12s):** The object maintains a constant velocity of -2 m/s.7. **Interval G (12s - 14s):** The object accelerates from -2 m/s to 0 m/s.8. **Interval H (14s - 16s):** The object accelerates from 0 m/s to 2 m/s.#### ObjectiveUse the velocity vs. time graph to find the average acceleration over the entire interval.#### Answer Choices- A. 0.36 m/s²- B. 0.07 m/s²- C. 0 m/s²- D. -0.07 m/s²- E. -0.36 m/s²**Explanation:**To find the average acceleration, consider the total change in velocity over the total time period. Calculate using the initial and final velocities and the complete time interval from 0s to 16s. ### Graph AnalysisEach graph below shows the position of an object as a function of time. From greatest to least, rank the distance of the object at 4 seconds.#### Graph A:- **Position (m)** vs. **Time (s)**- At 4 seconds, the position is 4 meters.#### Graph B:- **Position (m)** vs. **Time (s)**- At 4 seconds, the position is 8 meters. #### Graph C:- **Position (m)** vs. **Time (s)**- At 4 seconds, the position is 0 meters. #### Graph D:- **Position (m)** vs. **Time (s)**- At 4 seconds, the position is 4 meters.#### Answer Options:- **A. B > D = A > C**- **B. A = B = C = D**- **C. A > B > C > D**- **D. D > C > B > A**### Question 20An airplane starts from rest and accelerates at \( 12.6 \, \text{m/s}^2 \). What is its speed at the end of a 1790 m long runway?#### Answer Options:- **A. 212 m/s**- **B. 34500 m/s**- **C. 131 m/s**- **D. 4320 m/s**- **E. none of the above**

Use the velocity vs. time graph below to find the average acceleration over the entire interval. Velocity, m/s 4- C В D H 6. 8. 10 12, 14 16 Time, s -2- A E G F O A. 0.36 m/s2 O B. 0.07 m/s2 O C.0 m/s² O D. _0.07 m/s² E. 0 36 m/s2 2.

Use the velocity vs. time graph below to find the average acceleration over the entire interval. Velocity, m/s 4- C В D H 6. 8. 10 12, 14 16 Time, s -2- A E G F O A. 0.36 m/s2 O B. 0.07 m/s2 O C.0 m/s² O D. _0.07 m/s² E. 0 36 m/s2 2.

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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