A rider on horseback moves according to the velocity vs. time graph shown. Find the displacement of the rider over segment C. 8 B A 10 15 20 25 Time, t (s) О А. 20 m О В. 10 m О С.-10 m O D. -20 m/s O E. none of the above Velocity, v (m/s)
Displacement, Velocity and Acceleration
In classical mechanics, kinematics deals with the motion of a particle. It deals only with the position, velocity, acceleration, and displacement of a particle. It has no concern about the source of motion.
Linear Displacement
The term "displacement" refers to when something shifts away from its original "location," and "linear" refers to a straight line. As a result, “Linear Displacement” can be described as the movement of an object in a straight line along a single axis, for example, from side to side or up and down. Non-contact sensors such as LVDTs and other linear location sensors can calculate linear displacement. Non-contact sensors such as LVDTs and other linear location sensors can calculate linear displacement. Linear displacement is usually measured in millimeters or inches and may be positive or negative.
![**Problem Overview:**
A rider on horseback moves according to the velocity vs. time graph shown. Find the displacement of the rider over segment C.
**Graph Description:**
- **Axes:**
- The x-axis represents time in seconds (s) from 0 to 25 seconds.
- The y-axis represents velocity in meters per second (m/s) from 0 to 8 m/s.
- **Segments:**
- The graph is divided into three line segments labeled A, B, and C.
- **Segment A**:
- From (0 s, 0 m/s) to (10 s, 2 m/s).
- **Segment B**:
- From (10 s, 2 m/s) to (15 s, 6 m/s).
- **Segment C**:
- From (15 s, 6 m/s) to (25 s, 2 m/s).
**Question Options for Displacement Over Segment C:**
- A. 20 m
- B. 10 m
- C. -10 m
- D. -20 m/s
- E. none of the above
**Solution:**
To find the displacement over segment C, calculate the area under the velocity-time graph from 15 to 25 seconds. The area can be calculated as a trapezoid with bases 6 m/s and 2 m/s and a height of 10 s.
- **Trapezoid Area Formula:**
\[
\text{Area} = \frac{1}{2} \times (\text{Base}_1 + \text{Base}_2) \times \text{Height}
\]
\[
\text{Area} = \frac{1}{2} \times (6 + 2) \times 10 = 40 \, \text{m}
\]
Thus, the displacement over segment C is **40 meters**. However, none of the provided options match this result, suggesting option E, "none of the above," might be correct.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fbe8fa3d5-9008-42ca-a40d-155ab43de8c8%2F03a6e8d7-620e-4967-b93f-a2f09b690e70%2Ffcrsnvm_processed.png&w=3840&q=75)


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