Which of the following is a motion diagram between t = 5.00 s and t = 9.00 s?a. options in atttachemnt b. What is the acceleration between t = 5.00 s and t = 9.00 s? If the acceleration is to +x-direction, enter a positive value and if the acceleration is to –x-direction, enter a negative value. anser in m/s^2 ### Velocity vs. Time Graph Explanation#### Velocity-Time Graph OverviewThis graph represents the velocity (\(v_x\)) in meters per second (m/s) of an object moving along the x-axis plotted against time (\(t\)) in seconds (s).#### Detailed Graph Analysis1. **Axes:** - The horizontal axis represents time, \(t\) in seconds (s), and ranges from 0 to 14 seconds. - The vertical axis represents velocity, \(v_x\) in meters per second (m/s), ranging from 0 to 50 m/s.2. **Initial Velocity Constant (0s to 6s):** - From time \(t = 0 \text{s}\) to \(t = 6 \text{s}\), the velocity, \(v_x\), is constant at 20 m/s. - This indicates the object is moving at a steady velocity during this period.3. **Acceleration Phase (6s to 9s):** - Between \(t = 6 \text{s}\) and \(t = 9 \text{s}\), there is a sharp acceleration. - The velocity increases linearly from 20 m/s to 40 m/s, indicating the object is speeding up.4. **Deceleration Phase (9s to 13s):** - From \(t = 9 \text{s}\) to \(t = 13 \text{s}\), there is a linear decrease in velocity from 40 m/s back to 0 m/s, indicating the object is slowing down.5. **Resting State (13s to 14s):** - Between \(t = 13 \text{s}\) and \(t = 14 \text{s}\), the velocity stays at 0 m/s. - This signifies that the object has stopped moving.### Key Points to Note:- **Constant Velocity:** When the graph is a horizontal line (between 0s to 6s), the object’s velocity is steady.- **Increasing Velocity:** A positive slope (upwards line from 6s to 9s) reflects acceleration.- **Decreasing Velocity:** A negative slope (downwards line from 9s to 13s) represents deceleration.- **No Movement:** A horizontal line at 0 m/s (from 13s to 14s) indicates the object ### Multiple Choice1. **Option A:** ![Graph for Option A](https://via.placeholder.com/150) A graphical representation of distance (in meters) versus time (in seconds). The data points correspond to the following time intervals: - \( t = 5.00 \, s \): 100 meters - \( t = 6.00 \, s \): 130 meters - \( t = 7.00 \, s \): 160 meters - \( t = 8.00 \, s \): 190 meters - \( t = 9.00 \, s \): 250 meters The graph shows a marked upward arrow at \( t = 9.00 \, s \), indicating an accelerating trend.2. **Option B:** ![Graph for Option B](https://via.placeholder.com/150) A graphical representation of distance (in meters) versus time (in seconds). The data points correspond to the following time intervals: - \( t = 5.00 \, s \): 100 meters - \( t = 6.00 \, s \): 105 meters - \( t = 7.00 \, s \): 110 meters - \( t = 8.00 \, s \): 115 meters - \( t = 9.00 \, s \): 125 meters The graph shows a marked upward arrow at \( t = 9.00 \, s \), indicating a slight accelerating trend.3. **Option C:** ![Graph for Option C](https://via.placeholder.com/150) A graphical representation of distance (in meters) versus time (in seconds). The data points correspond to the following time intervals: - \( t = 5.00 \, s \): 100 meters - \( t = 6.00 \, s \): 110 meters - \( t = 7.00 \, s \): 120 meters - \( t = 8.00 \, s \): 130 meters - \( t = 9.00 \, s \): 150 meters The graph shows a marked upward arrow at \( t = 9.00 \, s \), indicating an accelerating trend.

Name: Which of the following is a motion diagram between t = 5.00 s and t =
Uploaded: 2024-03-05T11:56:34.000Z
Channel: Bartleby
Description: Which of the following is a motion diagram between t = 5.00 s and t = 9.00 s?a. options in atttachemnt b. What is the acceleration between t = 5.00 s and t = 9.00 s? If the acceleration is to +x-direction, enter a positive value and if the accelerati