A plot of velocity versus time for a car for the first 15 seconds of motion is shown in the diagram below. v, m/s 60 The distance traveled during these 15 seconds is: O 1.5 km O 650 m O 450 m O 275 m O 85 m 40 10 I 5 10 15 t, S

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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### Problem Statement

A plot of velocity versus time for a car for the first 15 seconds of motion is shown in the diagram below.

### Diagram Description

The diagram is a velocity-time graph with velocity (\(v\), in meters per second) on the vertical axis and time (\(t\), in seconds) on the horizontal axis. The graph shows the following:

- At \(t = 0\) seconds, the velocity is 60 m/s.
- From \(t = 0\) to \(t = 5\) seconds, the velocity decreases linearly from 60 m/s to 20 m/s.
- From \(t = 5\) to \(t = 15\) seconds, the velocity remains constant at 20 m/s.

### Question

The distance traveled during these 15 seconds is:

- ○ 1.5 km
- ○ 650 m
- ○ 450 m
- ○ 275 m
- ○ 85 m

### Explanation

To find the total distance traveled, you need to calculate the area under the velocity-time graph within the specified time frame. This involves finding the area of a trapezoid from \(t = 0\) to \(t = 5\) seconds and a rectangle from \(t = 5\) to \(t = 15\) seconds.
Transcribed Image Text:### Problem Statement A plot of velocity versus time for a car for the first 15 seconds of motion is shown in the diagram below. ### Diagram Description The diagram is a velocity-time graph with velocity (\(v\), in meters per second) on the vertical axis and time (\(t\), in seconds) on the horizontal axis. The graph shows the following: - At \(t = 0\) seconds, the velocity is 60 m/s. - From \(t = 0\) to \(t = 5\) seconds, the velocity decreases linearly from 60 m/s to 20 m/s. - From \(t = 5\) to \(t = 15\) seconds, the velocity remains constant at 20 m/s. ### Question The distance traveled during these 15 seconds is: - ○ 1.5 km - ○ 650 m - ○ 450 m - ○ 275 m - ○ 85 m ### Explanation To find the total distance traveled, you need to calculate the area under the velocity-time graph within the specified time frame. This involves finding the area of a trapezoid from \(t = 0\) to \(t = 5\) seconds and a rectangle from \(t = 5\) to \(t = 15\) seconds.
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