The differential equation is: d²y k (y+s+l – h + mg dt2 m k The form of the solution that we consider now is: y(t) = yo + A cos(wt + 4) Solve for yo (in cm) with these parameters. If you need more information, enter -100000. • s = 9 cm • h = 167 cm •m = 500 grams • e = (relaxed length) = 7 cm k = (spring constant) = 0.05 N/cm If you are stumped, try this substitution: t = = (1/2 – 4)/w.
Displacement, Velocity and Acceleration
In classical mechanics, kinematics deals with the motion of a particle. It deals only with the position, velocity, acceleration, and displacement of a particle. It has no concern about the source of motion.
Linear Displacement
The term "displacement" refers to when something shifts away from its original "location," and "linear" refers to a straight line. As a result, “Linear Displacement” can be described as the movement of an object in a straight line along a single axis, for example, from side to side or up and down. Non-contact sensors such as LVDTs and other linear location sensors can calculate linear displacement. Non-contact sensors such as LVDTs and other linear location sensors can calculate linear displacement. Linear displacement is usually measured in millimeters or inches and may be positive or negative.
![The differential equation is:
d²y
k
(y+s+l – h +
mg
dt2
m
k
The form of the solution that we consider now is:
y(t) = yo + A cos(wt + 4)
Solve for yo (in cm) with these parameters. If you need more information, enter -100000.
• s = 9 cm
• h = 167 cm
•m = 500 grams
• e = (relaxed length) = 7 cm
k = (spring constant) = 0.05 N/cm
If you are stumped, try this substitution: t = (T/2 –e)/w.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc43df1b6-679c-44d0-806b-554719efc373%2F084f1338-f8dd-4c1e-bba7-98bcc0fce610%2Fuv3oqev_processed.png&w=3840&q=75)
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