Assuming a cubic crystal system, make a sketch of the following planes. a) (001), b) (111) c) (123), d) (110), e) (010), f) (ÏÏÏ), g) (221) h) (010)
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- Semiconductors are ____________. conductors insulators half conductors none of the aboveWhat would most likely to be a semiconductor considering the following number of valence electrons? a) 8 b) 1 c) 7 d) 4 e) 2Which statement is not true about an extrinsic semiconductor? They do not have equal numbers charge carriers. Their impurities do not affect their electrical behavior. They can be doped with another element by a process known as doping process. They are chemically not pure. Their electrical properties can be tuned.
- use the constant voltage drop model in analyzing the diode circuit below: 10 92 V₁ (+ M 1 V D₁ If V₁ is -3 V, what would be the state of the diodes? A. D₁ and D₂ are both OFF C B. D₁ is OFF and D₂ is ON - 1 V D₂ C. D₁ is ON and D₂ is OFF D. D₁ and D₂ are both ON + 1092 VoSiAs is a semiconductor. If Si is replaced by another element, which of the following element will make a p-type semiconductor ? P Al Sb SeMost common materials for semiconductors are
- Use Kirchhoff's law method Indicates the conduction status of the diode The result is the table of current and voltage values for each element Incorporates the diode conduction voltage if applicable 7) R1 - IK E1 R2 lov (+ D1 esi D2@sIf one of the diodes in the figure below is open, the average voltage across the load is: (a) increases (b) decreases (c) does not changeCrystallographic positions Crystallographic position is denoted by three numbers, which are coefficients of the position vector, e.g. ½½½ for the red atom. Here the 'new' atom is at a/2 + b/2 + c/2 Silicon crystal has so-called "diamond type lattice". Each Si atom has 4 nearest neighbors. Diamond lattice starts with a FCC lattice and then adds four additional INTERNAL atoms at locations r = a/4+b/4+c/4 away from each of the atoms. In other words, diamond lattice is formed by two FCC lattices sifted by the vector r.
- For the diode circuit shown below, indicate the ON/OFF condition for all the diodes given VA and VB values. Calculate Vout, Vx and all the currents that flow through the diodes. Summarize your result using a table. +4V VA VB VA OV OV 4V D₁ D₂ X 5ΚΩ D3 VB OV 4V 4V -2V 5ΚΩ VOUTFinding crystallographic direction Z pt. 2 head pt. 1: ៩ Example 2: pt. 1 x₁ = a, y₁ = b/2, z₁ = 0 pt. 2 x2=-a, y₂ = b, Z₂ = c -a-a b-b/2 c-0 a b c tail => -2, 1/2, 1 Multiplying by 2 to eliminate the fraction -4,1,2 => [412] where the overbar represents a negative index families of directionsDetermine the following

