Assume that a simple random sample has been selected from a normally distributed population. Find the test statistic, P-value, critical value(s), and state the final conclusion. Test the claim that for the population of history exams, the mean score is 80. Sample data are summarized as n-16 x-845, and s-112 Use a significance level of a-0.01. Seleccione una: O A. a = 0.01 Test statistic:t=-1,607 P-value: p = 0.8711 Critical values: t = ±1.96 Because the test statistic, t < 1.96, we do not reject the null hypothesis. There is sufficient evidence to warrant rejection of the claim that the mean score is 80. O B. a = 0.01 Test statistic: t= -1.607 P-value: p = 0.1289 Critical values: t = 2.947 Because the test statistic, t < 2.947, we do not reject the null hypothesis. There is not sufficient evidence to warrant rejection of the claim that the mean score is 80. O C.a = 0.01 Test statistic: t 1.607 P-value: p = 0.1289 Critical values: t = +2.947 Because the test statistic, t< 2.947, we do not reject the null hypothesis. There is sufficient evidence to warrant rejection of the claim that the mean score is 80. O D. a = 0.01 Test statistic: t 1.607 P-value: p = 0.1289 Critical values: t = 1.96 Because the test statistic, t< 1.96, we do not reject the null hypothesis. There is sufficient evidence to warrant rejection of the claim that the mean score is 80. O E. a = 0.01 Test statistic: t = 1.607 P-value: p = 0.1289 Critical values: t= +2.947 Because the test statistic, t< 2.947, we do not reject the null hypothesis. There is not sufficient evidence to warrant rejection of the claim that the mean score is 80.
Assume that a simple random sample has been selected from a normally distributed population. Find the test statistic, P-value, critical value(s), and state the final conclusion. Test the claim that for the population of history exams, the mean score is 80. Sample data are summarized as n-16 x-845, and s-112 Use a significance level of a-0.01. Seleccione una: O A. a = 0.01 Test statistic:t=-1,607 P-value: p = 0.8711 Critical values: t = ±1.96 Because the test statistic, t < 1.96, we do not reject the null hypothesis. There is sufficient evidence to warrant rejection of the claim that the mean score is 80. O B. a = 0.01 Test statistic: t= -1.607 P-value: p = 0.1289 Critical values: t = 2.947 Because the test statistic, t < 2.947, we do not reject the null hypothesis. There is not sufficient evidence to warrant rejection of the claim that the mean score is 80. O C.a = 0.01 Test statistic: t 1.607 P-value: p = 0.1289 Critical values: t = +2.947 Because the test statistic, t< 2.947, we do not reject the null hypothesis. There is sufficient evidence to warrant rejection of the claim that the mean score is 80. O D. a = 0.01 Test statistic: t 1.607 P-value: p = 0.1289 Critical values: t = 1.96 Because the test statistic, t< 1.96, we do not reject the null hypothesis. There is sufficient evidence to warrant rejection of the claim that the mean score is 80. O E. a = 0.01 Test statistic: t = 1.607 P-value: p = 0.1289 Critical values: t= +2.947 Because the test statistic, t< 2.947, we do not reject the null hypothesis. There is not sufficient evidence to warrant rejection of the claim that the mean score is 80.
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Question
![Assume that a simple random sample has been selected from a normally distributed population. Find the test statistic, P-value, critical value(s),
and state the final conclusion.
Test the claim that for the population of history exams, the mean score is 80. Sample data are summarized as n=16, x-845, and s-11.2 Use a significance
level of a-0.01.
Seleccione una:
O A. a = 0.01
Test statistic:t= -1.607
P-value: p = 0.8711
Critical values: t = 1.96
Because the test statistic, t < 1.96, we do not reject the null hypothesis. There is sufficient evidence to warrant rejection of the claim that the mean
score is 80.
O B. a = 0.01
Test statistic: t = -1.607
P-value: p = 0.1289
Critical values: t = ±2.947
Because the test statistic, t < 2.947, we do not reject the null hypothesis. There is not sufficient evidence to warrant rejection of the claim that the
mean score is 80.
O C. a = 0.01
Test statistic: t = 1.607
P-value: p = 0.1289
Critical values: t = +2.947
Because the test statistic, t < 2.947, we do not reject the null hypothesis. There is sufficient evidence to warrant rejection of the claim that the mean
score is 80.
O D. a = 0.01
Test statistic: t 1.607
P-value: p = 0.1289
Critical values: t = +1.96
Because the test statistic, t< 1.96, we do not reject the null hypothesis. There is sufficient evidence to warrant rejection of the claim that the mean
score is 80.
O E. a = 0.01
Test statistic: t = 1.607
P-value: p = 0.1289
Critical values: t = 2.947
Because the test statistic, t< 2.947, we do not reject the null hypothesis. There is not sufficient evidence to warrant rejection of the claim that the
mean score is 80.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F00fbdba4-42bc-4346-9411-04714e88dad2%2F4a949fc3-a719-4fcf-8bdd-77786afd1856%2Feohk08h_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Assume that a simple random sample has been selected from a normally distributed population. Find the test statistic, P-value, critical value(s),
and state the final conclusion.
Test the claim that for the population of history exams, the mean score is 80. Sample data are summarized as n=16, x-845, and s-11.2 Use a significance
level of a-0.01.
Seleccione una:
O A. a = 0.01
Test statistic:t= -1.607
P-value: p = 0.8711
Critical values: t = 1.96
Because the test statistic, t < 1.96, we do not reject the null hypothesis. There is sufficient evidence to warrant rejection of the claim that the mean
score is 80.
O B. a = 0.01
Test statistic: t = -1.607
P-value: p = 0.1289
Critical values: t = ±2.947
Because the test statistic, t < 2.947, we do not reject the null hypothesis. There is not sufficient evidence to warrant rejection of the claim that the
mean score is 80.
O C. a = 0.01
Test statistic: t = 1.607
P-value: p = 0.1289
Critical values: t = +2.947
Because the test statistic, t < 2.947, we do not reject the null hypothesis. There is sufficient evidence to warrant rejection of the claim that the mean
score is 80.
O D. a = 0.01
Test statistic: t 1.607
P-value: p = 0.1289
Critical values: t = +1.96
Because the test statistic, t< 1.96, we do not reject the null hypothesis. There is sufficient evidence to warrant rejection of the claim that the mean
score is 80.
O E. a = 0.01
Test statistic: t = 1.607
P-value: p = 0.1289
Critical values: t = 2.947
Because the test statistic, t< 2.947, we do not reject the null hypothesis. There is not sufficient evidence to warrant rejection of the claim that the
mean score is 80.
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