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The accompunying thbie shows the costs per very good removal, significant difference. Click here to view the toothpaste data and ANOVA table. Click here to view a description of the Scheffe Test. The critical value is O (Round to two decimal places as needed.) The test statistic for comparing the Very Good toothpaste to the Good toothpaste is. Toothpaste data and ANOVA table Scheffé test (Round to two decimal places as needed.) The test statistic for comparing the Very Good toothpaste to the Fair toothpaste is. Very Good Good Fair 0.46 0.48 0.41 If the null hypothesis is rejected in a one-way then a Scheffé Test can be performed to find difference. In a Scheffé Test, the means are c with three means you would have these comp (Round to two decimal places as needed.) 0.61 0.33 0.64 0.45 O 58 The test statistic for Dndae lor comparning the Good toothpaste to the Fair toothpaste is mal places as peod to tuo

The accompunying thbie shows the costs per very good removal, significant difference. Click here to view the toothpaste data and ANOVA table. Click here to view a description of the Scheffe Test. The critical value is O (Round to two decimal places as needed.) The test statistic for comparing the Very Good toothpaste to the Good toothpaste is. Toothpaste data and ANOVA table Scheffé test (Round to two decimal places as needed.) The test statistic for comparing the Very Good toothpaste to the Fair toothpaste is. Very Good Good Fair 0.46 0.48 0.41 If the null hypothesis is rejected in a one-way then a Scheffé Test can be performed to find difference. In a Scheffé Test, the means are c with three means you would have these comp (Round to two decimal places as needed.) 0.61 0.33 0.64 0.45 O 58 The test statistic for Dndae lor comparning the Good toothpaste to the Fair toothpaste is mal places as peod to tuo

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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The accompanying table shows the costs per ounce (in dollars) for a sample of toothpastes exhibiting very good stain removal, good stain removal, and fair stain removal. At a =0.05, there is evidence that at least one mean cost per ounce is different from the others. Perform a Scheffé Test to determine which means have a significant difference, Click here to view the toothpaste data and ANOVA table. Click here to view a description of the Scheffé Test. ..... The critical value is. (Round to two decimal places as needed.) - X Toothpaste data and ANOVA table Scheffé test E...... The test statistic for comparing the Very Good toothpaste to the Good toothpaste is (Round to two decimal places as needed.) The test statistic for comparing the Very Good toothpaste to the Fair toothpaste is Very Good Good Fair If the null hypothesis is rejected in a one-way ANOVA test of three or more means, then a Scheffé Test can be performed to find which means have a significant difference. In a Scheffé Test, the means are compared two at a time. For instance, with three means you would have these comparisons: x, versus x2, x1 versus x3, (Round to two decimal places as needed.) 0.46 0.61 0.33 0.48 0.64 0.45 The test statistic for comparing the Good toothpaste to the Fair toothpaste is. 0.41 0.58 0.44 (Round to two decimal places as needed.) 0.36 0.75 0.59 - 0.47 0.45 Which means have a significant difference? Select all that apply. and x, versus X3. For each comparison, calculate where 0.51 SSw 1 1 + O A. Good and Fair XVery Good = 0.448 Σι - 1) na no O B. Very Good and Good XGood = 0.606 Xa and x, are the means being compared and ng and n, are the corresponding O C. Very Good and Fair XFair = 0.453 sample sizes. Calculate the critical value by multiplying the critical value of the one-way ANOVA test by k- 1, where k is the number of samples. Then compare the value that is calculated using the formula above with the critical value. The means have a significant difference when the value calculated using the formula above is greater than the critical value. O D. No specific pair of means is significantly different. Variation Sum of Squares Degrees of Freedom Mean Squares Between 0.08116 2 0.04058 5.09 Within 0.09568 12 0.00797 Print Done Print Done
Transcribed Image Text:The accompanying table shows the costs per ounce (in dollars) for a sample of toothpastes exhibiting very good stain removal, good stain removal, and fair stain removal. At a =0.05, there is evidence that at least one mean cost per ounce is different from the others. Perform a Scheffé Test to determine which means have a significant difference, Click here to view the toothpaste data and ANOVA table. Click here to view a description of the Scheffé Test. ..... The critical value is. (Round to two decimal places as needed.) - X Toothpaste data and ANOVA table Scheffé test E...... The test statistic for comparing the Very Good toothpaste to the Good toothpaste is (Round to two decimal places as needed.) The test statistic for comparing the Very Good toothpaste to the Fair toothpaste is Very Good Good Fair If the null hypothesis is rejected in a one-way ANOVA test of three or more means, then a Scheffé Test can be performed to find which means have a significant difference. In a Scheffé Test, the means are compared two at a time. For instance, with three means you would have these comparisons: x, versus x2, x1 versus x3, (Round to two decimal places as needed.) 0.46 0.61 0.33 0.48 0.64 0.45 The test statistic for comparing the Good toothpaste to the Fair toothpaste is. 0.41 0.58 0.44 (Round to two decimal places as needed.) 0.36 0.75 0.59 - 0.47 0.45 Which means have a significant difference? Select all that apply. and x, versus X3. For each comparison, calculate where 0.51 SSw 1 1 + O A. Good and Fair XVery Good = 0.448 Σι - 1) na no O B. Very Good and Good XGood = 0.606 Xa and x, are the means being compared and ng and n, are the corresponding O C. Very Good and Fair XFair = 0.453 sample sizes. Calculate the critical value by multiplying the critical value of the one-way ANOVA test by k- 1, where k is the number of samples. Then compare the value that is calculated using the formula above with the critical value. The means have a significant difference when the value calculated using the formula above is greater than the critical value. O D. No specific pair of means is significantly different. Variation Sum of Squares Degrees of Freedom Mean Squares Between 0.08116 2 0.04058 5.09 Within 0.09568 12 0.00797 Print Done Print Done
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