Assume that a simple random sample has been selected from a normally distributed population. Find the test statistic, P-value, critical value(s), and state the final conclusion Test the claim that for the population of history exams, the mean score is 80. Sample data are summarized as n = 16, = 84.5, and s= 11.2. Use a significance level of a = 0.01. Select the correct test statistic and critical value.
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A: Given Data: n=4x¯=62.1s=8.3
Assume that a simple random sample has been selected from a
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- an automobile engineer claims that 1in 10 automobile accidents are due to driver fatigue . if a random sample of 5 accidents observed , then the probabilty that 3 accidentsare due to drive fatigue isThe results of a study showed that heterosexual women, during ovulation, were significantly better at correctly identifying the marriage status of a man from a photograph of his face than women who were not ovulating. Near ovulation, on average women correctly identified the marriage status of about 67% of the 100 men shown to them. Assume that the sample distribution for this study is unimodal and symmetric and that the samples are collected randomly. If this is the probability of correctly identifying the marriage status of a man in any given photograph, what is the probability a woman would correctly classify 79 or more of the men? What is the probability?The United States Bureau of Labor Statistics (BLS) conducts the Quarterly Census of Employment and Wages (QCEW) and reports a variety of information on each county in America. In the third quarter of 2016, the QCEW reported the total taxable earnings, in millions, of all wage earners in all 3222 counties in America. Suppose that James is an economist who collects a simple random sample of the total taxable earnings of workers in 52 American counties during the third quarter of 2016. According to the QCEW, the true population mean and standard deviation of taxable earnings, in millions of dollars, by county are μ=28.29 and σ=33.493, respectively. Let ?X be the total taxable earnings, in millions, of all wage earners in a county. The mean total taxable earnings of all wage earners in a county across all the counties in James' sample is x¯. Use the central limit theorem (CLT) to determine the probability ? that the mean taxable wages in James' sample of 52 counties will be less than $29…
- A manufacturer of widgets wants to test a new widget-producing machine to determine if it can make an average of 25 widgets per second before deciding to invest in the machine. The standard to reject the new machine is if it makes an average of less than 25 widgets per second. Here are data from a small random sample:25.6, 26.2, 22.5, 20.5, 26.4, 27.4, 23.6, 26.9, 25.7, 24.9Assuming the population follows a normal distribution, is there evidence that the new machine should be rejected at the 0.01 significance level? State the hypotheses, list and check the conditions, calculate the test statistic, find the p-value, and make a conclusion in a complete sentence related to the scenario.The U.S. Energy Information Administration claimed that U.S. residential customers used an average of 10,476 kilowatt hours (kWh) of electricity this year. A local power company believes that residents in their area use more electricity on average than EIA's reported average. To test their claim, the company chooses a random sample of 153 of their customers and calculates that these customers used an average of 10,767 kWh of electricity last year. Assuming that the population standard deviation is 2478 kWh, is there sufficient evidence to support the power company's claim at the 0.05 level of significance? Step 3 of 3: Draw a conclusion and interpret the decision.The U.S. Energy Information Administration claimed that U.S. residential customers used an average of 10,069 kilowatt hours (kWh) of electricity this year. A local power company believes that residents in their area use more electricity on average than EIA's reported average. To test their claim, the company chooses a random sample of 171 of their customers and calculates that these customers used an average of 10,461 kWh of electricity last year. Assuming that the population standard deviation is 2973 kWh, is there sufficient evidence to support the power company's claim at the 0.01 level of significance? Step 3 of 3: Draw a conclusion and interpret the decision.
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- One cable company claims that it has excellent customer service. In fact, the company advertises that a technician will arrive within 45 minutes after a service call is placed. One frustrated customer believes this is not accurate, claiming that it takes over 45 minutes for the cable technician to arrive. The customer asks a simple random sample of 25 other cable customers how long it has taken for the cable technician to arrive when they have called for one. The sample mean for this group is 47.9 minutes with a standard deviation of 7.6 minutes. Assume that the population distribution is approximately normal. Test the customer's claim at the 0.01 level of significance. Step 1 of 3: State the null and alternative hypotheses for the test. Fill in the blank below. Ho : μ = 45 Ha:μ 45Female undergraduates in randomized groups of 15 took part in a self-esteem study. The study measured an index of self-esteem from the point of view of competence, social acceptance, and physical attractiveness. Let x1, x2, and x3 be random variables representing the measure of self-esteem through x1 (competence), x2 (social acceptance), and x3 (attractiveness). Higher index values mean a more positive influence on self- esteem. Variable Sample Mean Standard Deviation Population Size Мean 15 19.48 2.92 X1 X2 X3 (a) Find a 90% confidence interval for u1 - 42. (Round your answers to two decimal places.) lower limit 15 19.90 3.98 H2 15 17.42 3.60 upper limit (b) Find a 90% confidence interval for u1 - 43. (Round your answers to two decimal places.) lower limit upper limit (c) Find a 90% confidence interval for u2 - 13. (Round your answers to two decimal places.) lower limit upper limitAn adventure company runs two obstacle courses, Fundash and Coolsprint, with similar designs. Since Fundash was built on rougher terrain, the designer of the courses suspects that the mean completion time of Fundash is greater than the mean completion time of Coolsprint. To test this, she selects 230 Fundash runners and 210 Coolsprint runners. (Consider these as independent random samples of the Fundash and Coolspring runners.) The 230 Fundash runners complete the course with a mean time of 77.9 minutes and a standard deviation of 6.6 minutes. The 210 individuals complete Coolsprint with a mean time of 76.6 minutes and a standard deviation of 7.3 minutes. Assume that the population standard deviations of the completion times can be estimated to be the sample standard deviations, since the samples that are used to compute them are quite large. At the 0.05 level of significance, is there enough evidence to support the claim that the mean completion time, U1, of Fundash is greater than…