One cable company claims that it has excellent customer service. In fact, the company advertises that a technician will arrive within 35 minutes after a service call is placed. One frustrated customer believes this is not accurate, claiming that it takes over 35 minutes for the cable technician to arrive. The customer asks a simple random sample of 4 other cable customers how long it has taken for the cable technician to arrive when they have called for one. The sample mean for this group is 39.1 minutes with a standard deviation of 2.6 minutes. Assume that the population distribution is approximately normal. Test the customer's claim at the 0.10 level of significance. Step 1 of 3: State the null and alternative hypotheses for the test. Fill in the blank below. Ho :4 = 35 35

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One cable company claims that it has excellent customer service. In fact, the company advertises that a technician will arrive within 35 minutes after
a service call is placed. One frustrated customer believes this is not accurate, claiming that it takes over 35 minutes for the cable technician to arrive.
The customer asks a simple random sample of 4 other cable customers how long it has taken for the cable technician to arrive when they have called
for one. The sample mean for this group is 39.1 minutes with a standard deviation of 2.6 minutes. Assume that the population distribution is
approximately normal. Test the customer's claim at the 0.10 level of significance.
Step 1 of 3: State the null and alternative hypotheses for the test. Fill in the blank below.
Ho : µ = 35
35
1: "H
Transcribed Image Text:One cable company claims that it has excellent customer service. In fact, the company advertises that a technician will arrive within 35 minutes after a service call is placed. One frustrated customer believes this is not accurate, claiming that it takes over 35 minutes for the cable technician to arrive. The customer asks a simple random sample of 4 other cable customers how long it has taken for the cable technician to arrive when they have called for one. The sample mean for this group is 39.1 minutes with a standard deviation of 2.6 minutes. Assume that the population distribution is approximately normal. Test the customer's claim at the 0.10 level of significance. Step 1 of 3: State the null and alternative hypotheses for the test. Fill in the blank below. Ho : µ = 35 35 1: "H
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