The sample data here is the cholesterol levels for 10 men diagnosed with high cholesterol. The first row represents levels from 10 men who did not use the drug and the second row from 10 different men who did use the drug. If we want to test the claim that the mean level for all men who use the drug is less than the mean for all men who do not use it, using the MS Excel output table below, which is the correct decision for the test at 5 % level of significance? No Drug 237 289 257 228 303 275 262 304 244 233 Drug 194 240 230 186 265 222 242 281 240 212 * t-Test: Two Sample Assuming Equal Variances |NO Drug Drug Mean 263.2 231.2 Variance 811.067 864 Observations 10 10 Pooled Variance 837.511 Hypothesized Mear df 18
The sample data here is the cholesterol levels for 10 men diagnosed with high cholesterol. The first row represents levels from 10 men who did not use the drug and the second row from 10 different men who did use the drug. If we want to test the claim that the mean level for all men who use the drug is less than the mean for all men who do not use it, using the MS Excel output table below, which is the correct decision for the test at 5 % level of significance? No Drug 237 289 257 228 303 275 262 304 244 233 Drug 194 240 230 186 265 222 242 281 240 212 * t-Test: Two Sample Assuming Equal Variances |NO Drug Drug Mean 263.2 231.2 Variance 811.067 864 Observations 10 10 Pooled Variance 837.511 Hypothesized Mear df 18
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter10: Statistics
Section10.3: Measures Of Spread
Problem 1GP
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Question
![The sample data here is the cholesterol levels for 10 men diagnosed with
high cholesterol. The first row represents levels from 10 men who did not
use the drug and the second row from 10 different men who did use the
drug. If we want to test the claim that the mean level for all men who use
the drug is less than the mean for all men who do not use it, using the MS
Excel output table below, which is the correct decision for the test at 5 %
level of significance? No Drug 237 289 257 228 303 275 262 304 244 233
Drug 194 240 230 186 265 222 242 281 240 212 *
t-Test: Two Sample Assuming Equal Variances
NO Drug Drug
Mean
263.2 231.2
Variance
811.067
864
Observations
10
10
Pooled Variance
837.511
Hypothesized Mear
df
18
t Stat
2.47252
P(T<=t) one tail
t Critical one tail
P(T<=t) two-tail
t Critical two tail
0.01181
1.73406
0.02362
2.10092
Do not reject Ho because the p-value is greater than the significance level.
Do not reject Ho because the p-value is less than the significance level.
Reject Ho because the significance level is less than the p-value.
Reject Ho because the p-value is less than the significance level.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F0b9bed71-fd20-49a3-9e11-5fdda8289409%2F75fd6ef6-b3b8-4a08-89d6-eb798750cb68%2Ff146bhd_processed.png&w=3840&q=75)
Transcribed Image Text:The sample data here is the cholesterol levels for 10 men diagnosed with
high cholesterol. The first row represents levels from 10 men who did not
use the drug and the second row from 10 different men who did use the
drug. If we want to test the claim that the mean level for all men who use
the drug is less than the mean for all men who do not use it, using the MS
Excel output table below, which is the correct decision for the test at 5 %
level of significance? No Drug 237 289 257 228 303 275 262 304 244 233
Drug 194 240 230 186 265 222 242 281 240 212 *
t-Test: Two Sample Assuming Equal Variances
NO Drug Drug
Mean
263.2 231.2
Variance
811.067
864
Observations
10
10
Pooled Variance
837.511
Hypothesized Mear
df
18
t Stat
2.47252
P(T<=t) one tail
t Critical one tail
P(T<=t) two-tail
t Critical two tail
0.01181
1.73406
0.02362
2.10092
Do not reject Ho because the p-value is greater than the significance level.
Do not reject Ho because the p-value is less than the significance level.
Reject Ho because the significance level is less than the p-value.
Reject Ho because the p-value is less than the significance level.
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