A data set includes data from student evaluations of courses. The summary statistics are n=95, x= 3.36, s=0.55. Use a 0.10 significance level to test the claim that the population of student course evaluations has a mean equal to 3.50. Assume that a simple random sample has been selected. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim. What are the null and alternative hypotheses? OA. Ho: H=3.50 H₁: μ>3.50 O C. Ho: H = 3.50 H₁: <3.50 C OB. Ho: H=3.50 H₁: μ*3.50 OD. Ho: μ#3.50 H₁: H=3.50

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A data set includes data from student evaluations of courses. The summary statistics are \( n = 95 \), \( \bar{x} = 3.36 \), \( s = 0.55 \). Use a 0.10 significance level to test the claim that the population of student course evaluations has a mean equal to 3.50. Assume that a simple random sample has been selected. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim.

**What are the null and alternative hypotheses?**

- **Option A:**  
  \( H_0: \mu = 3.50 \)  
  \( H_1: \mu > 3.50 \)

- **Option B:**  
  \( H_0: \mu = 3.50 \)  
  \( H_1: \mu \neq 3.50 \)

- **Option C:**  
  \( H_0: \mu = 3.50 \)  
  \( H_1: \mu < 3.50 \)

- **Option D:**  
  \( H_0: \mu = 3.50 \)  
  \( H_1: \mu = 3.50 \)
Transcribed Image Text:A data set includes data from student evaluations of courses. The summary statistics are \( n = 95 \), \( \bar{x} = 3.36 \), \( s = 0.55 \). Use a 0.10 significance level to test the claim that the population of student course evaluations has a mean equal to 3.50. Assume that a simple random sample has been selected. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim. **What are the null and alternative hypotheses?** - **Option A:** \( H_0: \mu = 3.50 \) \( H_1: \mu > 3.50 \) - **Option B:** \( H_0: \mu = 3.50 \) \( H_1: \mu \neq 3.50 \) - **Option C:** \( H_0: \mu = 3.50 \) \( H_1: \mu < 3.50 \) - **Option D:** \( H_0: \mu = 3.50 \) \( H_1: \mu = 3.50 \)
Expert Solution
Step 1: Determine the given data

From the provided information,

n equals 95
top enclose x equals 3.36
s equals 0.55
alpha equals 0.10

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