Suppose IQ scores were obtained for 20 randomly selected sets of couples. The 20 pairs of measurements yield x=99.05, y = 100.15, r=0.837, P-value = 0.000, and y=19.19+0.82x, where x represents the IQ score of the wife. Find the best predicted value of y given that the wife has an IQ of 108? Use a significance level of 0.05. Click the icon to view the critical values of the Pearson correlation coefficient r. The best predicted value of ŷ is. (Round to two decimal places as needed.)
Suppose IQ scores were obtained for 20 randomly selected sets of couples. The 20 pairs of measurements yield x=99.05, y = 100.15, r=0.837, P-value = 0.000, and y=19.19+0.82x, where x represents the IQ score of the wife. Find the best predicted value of y given that the wife has an IQ of 108? Use a significance level of 0.05. Click the icon to view the critical values of the Pearson correlation coefficient r. The best predicted value of ŷ is. (Round to two decimal places as needed.)
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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![### Critical Values of the Pearson Correlation Coefficient r
This table presents the critical values of the Pearson Correlation Coefficient \( r \) for significance levels \(\alpha = 0.05\) and \(\alpha = 0.01\). These critical values are used in hypothesis testing to determine if there is a statistically significant linear relationship between two variables.
**Columns Explanation:**
- **n**: Sample size
- **α = 0.05**: Critical value of \( r \) for a significance level of 0.05
- **α = 0.01**: Critical value of \( r \) for a significance level of 0.01
**How to Use this Table:**
To test the null hypothesis \( H_0: ρ = 0 \) against the alternative hypothesis \( H_1: ρ ≠ 0 \):
1. Calculate the Pearson correlation coefficient \( r \) from your sample data.
2. Select the appropriate critical value from the table based on your sample size \( n \) and desired significance level (\(\alpha = 0.05\) or \(\alpha = 0.01\)).
3. Reject the null hypothesis \( H_0 \) if the absolute value of \( r \) is greater than the critical value in the table.
**Table of Critical Values:**
| n | α = 0.05 | α = 0.01 |
|-----|----------|----------|
| 4 | 0.950 | 0.990 |
| 5 | 0.878 | 0.959 |
| 6 | 0.811 | 0.917 |
| 7 | 0.754 | 0.875 |
| 8 | 0.707 | 0.834 |
| 9 | 0.666 | 0.798 |
| 10 | 0.632 | 0.765 |
| 11 | 0.602 | 0.735 |
| 12 | 0.576 | 0.708 |
| 13 | 0.553 | 0.684 |
| 14 | 0.532 | 0.661 |
| 15 |](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F96fb4f59-e2d0-4223-b88e-b1f942117eac%2F5675f161-8e0c-4141-b334-4e1b9e4c9052%2Fscpwbfy_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Critical Values of the Pearson Correlation Coefficient r
This table presents the critical values of the Pearson Correlation Coefficient \( r \) for significance levels \(\alpha = 0.05\) and \(\alpha = 0.01\). These critical values are used in hypothesis testing to determine if there is a statistically significant linear relationship between two variables.
**Columns Explanation:**
- **n**: Sample size
- **α = 0.05**: Critical value of \( r \) for a significance level of 0.05
- **α = 0.01**: Critical value of \( r \) for a significance level of 0.01
**How to Use this Table:**
To test the null hypothesis \( H_0: ρ = 0 \) against the alternative hypothesis \( H_1: ρ ≠ 0 \):
1. Calculate the Pearson correlation coefficient \( r \) from your sample data.
2. Select the appropriate critical value from the table based on your sample size \( n \) and desired significance level (\(\alpha = 0.05\) or \(\alpha = 0.01\)).
3. Reject the null hypothesis \( H_0 \) if the absolute value of \( r \) is greater than the critical value in the table.
**Table of Critical Values:**
| n | α = 0.05 | α = 0.01 |
|-----|----------|----------|
| 4 | 0.950 | 0.990 |
| 5 | 0.878 | 0.959 |
| 6 | 0.811 | 0.917 |
| 7 | 0.754 | 0.875 |
| 8 | 0.707 | 0.834 |
| 9 | 0.666 | 0.798 |
| 10 | 0.632 | 0.765 |
| 11 | 0.602 | 0.735 |
| 12 | 0.576 | 0.708 |
| 13 | 0.553 | 0.684 |
| 14 | 0.532 | 0.661 |
| 15 |
![### Linear Regression and Predictive Analysis Based on IQ Scores
#### Scenario:
Suppose IQ scores were obtained for 20 randomly selected sets of couples. The 20 pairs of measurements yield the following statistics:
- The average IQ score (\(\bar{x}\)) of the wives: 99.05
- The average IQ score (\(\bar{y}\)) of the husbands: 100.15
- Pearson correlation coefficient (\(r\)): 0.837
- P-value: 0.000
- Regression line equation: \(\hat{y} = 19.19 + 0.82x\), where \(x\) represents the IQ score of the wife.
#### Task:
Find the best predicted value of \(\hat{y}\) given that the wife has an IQ of 108. Use a significance level of 0.05.
<br>
<span class="instruction">
Click the icon to view the critical values of the Pearson correlation coefficient \( r \).
</span>
<br>
<br>
Input the best predicted value of \(\hat{y}\) below:
(Please round to two decimal places as needed.)
\[ \hat{y} = \: \_\_\_\_\_ \]
#### Solution Steps:
1. **Substitute the wife's IQ score in the regression equation**:
Given the regression equation \(\hat{y} = 19.19 + 0.82x\), and the wife's IQ score \(x = 108\).
2. **Calculate the predicted value**:
\[
\hat{y} = 19.19 + 0.82 \times 108
\]
3. **Solve the equation to find \(\hat{y}\)**:
\[
\hat{y} = 19.19 + 88.56 = 107.75
\]
4. **Write the final predicted value**:
The best predicted value of \(\hat{y}\) is **107.75**.
This concludes the analysis of the predicted IQ score for the husband based on the given wife's IQ score using the linear regression model.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F96fb4f59-e2d0-4223-b88e-b1f942117eac%2F5675f161-8e0c-4141-b334-4e1b9e4c9052%2Fdwt6c97_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Linear Regression and Predictive Analysis Based on IQ Scores
#### Scenario:
Suppose IQ scores were obtained for 20 randomly selected sets of couples. The 20 pairs of measurements yield the following statistics:
- The average IQ score (\(\bar{x}\)) of the wives: 99.05
- The average IQ score (\(\bar{y}\)) of the husbands: 100.15
- Pearson correlation coefficient (\(r\)): 0.837
- P-value: 0.000
- Regression line equation: \(\hat{y} = 19.19 + 0.82x\), where \(x\) represents the IQ score of the wife.
#### Task:
Find the best predicted value of \(\hat{y}\) given that the wife has an IQ of 108. Use a significance level of 0.05.
<br>
<span class="instruction">
Click the icon to view the critical values of the Pearson correlation coefficient \( r \).
</span>
<br>
<br>
Input the best predicted value of \(\hat{y}\) below:
(Please round to two decimal places as needed.)
\[ \hat{y} = \: \_\_\_\_\_ \]
#### Solution Steps:
1. **Substitute the wife's IQ score in the regression equation**:
Given the regression equation \(\hat{y} = 19.19 + 0.82x\), and the wife's IQ score \(x = 108\).
2. **Calculate the predicted value**:
\[
\hat{y} = 19.19 + 0.82 \times 108
\]
3. **Solve the equation to find \(\hat{y}\)**:
\[
\hat{y} = 19.19 + 88.56 = 107.75
\]
4. **Write the final predicted value**:
The best predicted value of \(\hat{y}\) is **107.75**.
This concludes the analysis of the predicted IQ score for the husband based on the given wife's IQ score using the linear regression model.
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