Aro blenAW1RX14) is used ac a column to support an axial load OF 1784 KN and monentaabout the x -axıs equal to 180 KN - m, and moment about the y-axis of 6o KN -m. the columnsection has an unsupported height of 3. om consisting oF A34 steel with Fy =248 MPa whichIs braced against sideway. there oreno transverse loads andKx =1.0 and Ky=1.o. theColumn is bent in reverse Curvatucc about both axes wrth cqual end moments -Properties of Wi2X1611. compute thc allowable axial stressIF only axial stress30580.6 mm?areaOccurs .352.35 mmdeptha. compute the allowable bending stress about the x-aris317. 88 mmoF Flangethickness of plangeWicth3. compute the allowable bending stress about the y-axisthe interaction values por an al and bndingm ר.3722.99 mm1. Computestressesweb thicknesS36 38 X(03Sx1273 Xj03Rx144.78 mm81.28 mm

Question is based on the column subjected to axial load . Magnitude of load, moment about x and y…

as a column to support an axial load oF 1784 KN and moments AW 12 x 14) Is used about the x-axis equal to 180 KN -m, and moment about the y-axıs of 6o KN -m. the column sction has an unsupported height of 3.0m consisting of A 34 steel with Fy is braced against sideway. there ore Column Is 6ent in reverse Curvatucc about both axes wrth cqual end moment s- s 248 MPa which no transverse loads and KX 1.0 and Ky=1.o. the Properties of W 12x IuI 1. compute the allowable axial stress ip only axial stress 30580. G mm? area Occurs . 352.35 mm depth a. compute the allowade bending stress about the xaris 317.88 mm wicth of Flange 3. compute the allowable bending strees about the y-axis the nteraction values por an al nd buding 37.74 mm hickness of plange 22.99 mm beb thickness 1. Compute stresses. 36 38X(03 1273 Xjo3

as a column to support an axial load oF 1784 KN and moments AW 12 x 14) Is used about the x-axis equal to 180 KN -m, and moment about the y-axıs of 6o KN -m. the column sction has an unsupported height of 3.0m consisting of A 34 steel with Fy is braced against sideway. there ore Column Is 6ent in reverse Curvatucc about both axes wrth cqual end moment s- s 248 MPa which no transverse loads and KX 1.0 and Ky=1.o. the Properties of W 12x IuI 1. compute the allowable axial stress ip only axial stress 30580. G mm? area Occurs . 352.35 mm depth a. compute the allowade bending stress about the xaris 317.88 mm wicth of Flange 3. compute the allowable bending strees about the y-axis the nteraction values por an al nd buding 37.74 mm hickness of plange 22.99 mm beb thickness 1. Compute stresses. 36 38X(03 1273 Xjo3

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

Situation 13 - Using method of sections, determine the internal force of members 3-6 and 5-7. Use L = 2 m and P = 3 kN. 2P P 3P 1² M 45° 45° 3 L L 45° →→X
4-35. The column is constructed from high-strength con- crete and four A-36 steel reinforcing rods. If it is subject- ed to an axial force of 800 kN. determine the required diam- eter of each rod so that one-fourth of the load is carried by the steel and three-fourths by the concrete. E = 200 GPa, E = 25 GPa. %3D 800 kN 300 mm 300 mm Probs. 4-34/35
A rigid beam AB is hinged at A and is connected to an aluminium alloy bar BC at the other end. The beam is also supported on a steel post DE through a rigid bearing at D, as shown is figure. At no load condition, the beam is horizontal and there is an initial clearance 8 = 0.1 mm between the beam and rigid bearing. Determine the maximum permissible load W which may be applied at B if the axial stresses are not to exceed 120 N/mm² for steel and 140 N/mm² for the aluminium alloy. All the connections may be treated as smooth pins. Take E = 2 × 105 N/mm² for steel and E=0.8 x 105 N/mm² for aluminium alloy. A 0.2 m 0.1 m D Rigid beam 8- 0.1 mm Steel post (1500 mm²) E 0.3 m W C B Aluminium alloy bar (800 mm²) 0.4 m
HW A shaft composed of Segments Ac, CD and DB fastened to rigid supports and loaded as shown, for st G=83 GN/m², for Aluminum G =28GN/m² and for br G= 35 GN/m² Determine the maximum shearing Stress developed in each Segment? Steel d=25mm 2m Ans: TB-472 N.M, TAI = 9.1 TD=700N.. Tc=300N.m Aluminum d= Semm 1.5m & ₁ B Bronze d=25mm Im
Ana ly ze th e s ta tic a lly in de te rm in a te beam shown b y the s lo pe - de fle c tio n me thod. D ra w shear and bending - moment dia g ram s. Ske tch the de fo rm ed structu re. Conditio n of supports: A is hinge, B is hinge, C is h in ge. No te : Find the va lu es of MAB, M BA, MBC, M cCB , 8A, 0 B, and ec. Indic a te if it is zero. b A 3 lc 2 lc B DATA a P w ft ft kip ft k/ft 8 16 36 12 2.6 Required Va lu es Answer D irection ??? M AB MBA ??? MBC ??? ??? М св CB ??? A ??? ???
Determine the force in member DI of the loaded truss. Enter a positive number if in tension, negative if in compression. 4L B 5 m Answer: DI = i Save for Later 6L 6L D E 6L -5 m E H |Η 5 m AB=BC=CD= DE = EF = FG 4L L F L G Attempts: 0 of 1 used Submit Answer
Sispose that P = 30 kip, P=20 kip, and = 10 kip Figure ++. 400 San 184-399 30 Part A Determine the force in member GF of the bridge truss Express your answer in kilopounds to three significant figures. Enter negative value in the case of compression and positive value in the case of tension For Submit Part B Avec Fre Request Anst O? Determine the force in member PC of the bridge truss Express your answer in kilopounds to three significant figures. Enter negative value in the case of compression and positive value in the case of tension VAZO IT vec kip ? kip
2. The lap joint is fastened with four 30-mm-diameter rivets. The working stresses are 84 MPa for the rivets in shear and 84 MPa for the plates in bearing. Find the maximum safe axial load P that can be applied to the joint. Assume that the load is equally distributed among the rivets... 35 mm KATIN 160 mm
Answer only letter B with correct fbd
Determine the reactions at the supports. First, determine the equivalent load [kN] as required below and provide the location of each one from A [m]. The distributed load equivalents MUST be ONLY 2. One for the triangular distribution (FR1) and the other for the rectangular distribution (FR2). 6 kN/m Scale: 1 unit = 0.5 m FR1- FR2- Reaction1 (if present – specify [ Reaction2 (if present – specify [ {kN]; Location from A =, {kN]; Location from A = 1), at A = 1), at A = m [kN] [kN] Reaction1 (if present – specify [ Reaction2 (if present – specify [ 1), at B = 1), at B = [kN] [kN]
Determine the force in member BE if the force on E is changed to 525kN. 24 kN 17 kN BY 0.8 m # E 8 kN D 7 kN Answer: 1.5 m -1.5 m- S OKN Tension ON Compression
DETERMINE THE CONCRETE AND STEEL STRESS AT THE FIXED SUPPORT C.