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H.W No.1: The concrete I-beam of figure is pretensioned with four bounded stranded cables having total area (371 mm²). Eccentricity of the steel varies parabolically from 0 at the support to 193 mm at the center of 9 m span. The effective stress in steel after losses is 910 MPa. 254 mm 102 mm 76 mm 102 mm 193 mm 9 m a-what superimposed load will produce a balanced condition of external equivalent prestress load, such that uniform axial compression will be obtained in the concrete. b-what superimposed uniform distributed load will produce cracking of the beam, given the modulus of rupture f=3.28 MPa. c-compute the flexural strength of the beam and compare with the cracking moment. Use: fe = 27.6 MPa, fpy= 1469 MPa, fpu= 1724 MPa. Aps fps a= 0.85 feb --) M₁ = Aps fps (dp- Mn Mn = Pp fps bdp² (1 -0.59 x P x Ips) fci Apf = 0.85 f (b-bw)h fps Apw = 0.85 bw a fps a= Apwfps 0.85 fobw

H.W No.1: The concrete I-beam of figure is pretensioned with four bounded stranded cables having total area (371 mm²). Eccentricity of the steel varies parabolically from 0 at the support to 193 mm at the center of 9 m span. The effective stress in steel after losses is 910 MPa. 254 mm 102 mm 76 mm 102 mm 193 mm 9 m a-what superimposed load will produce a balanced condition of external equivalent prestress load, such that uniform axial compression will be obtained in the concrete. b-what superimposed uniform distributed load will produce cracking of the beam, given the modulus of rupture f=3.28 MPa. c-compute the flexural strength of the beam and compare with the cracking moment. Use: fe = 27.6 MPa, fpy= 1469 MPa, fpu= 1724 MPa. Aps fps a= 0.85 feb --) M₁ = Aps fps (dp- Mn Mn = Pp fps bdp² (1 -0.59 x P x Ips) fci Apf = 0.85 f (b-bw)h fps Apw = 0.85 bw a fps a= Apwfps 0.85 fobw

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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H.W No.1: The concrete I-beam of figure is pretensioned with four bounded stranded cables having total area (371 mm²). Eccentricity of the steel varies parabolically from 0 at the support to 193 mm at the center of 9 m span. The effective stress in steel after losses is 910 MPa. 254 mm 102 mm 76 mm 102 mm 193 mm 9 m a-what superimposed load will produce a balanced condition of external equivalent prestress load, such that uniform axial compression will be obtained in the concrete. b-what superimposed uniform distributed load will produce cracking of the beam, given the modulus of rupture f=3.28 MPa. c-compute the flexural strength of the beam and compare with the cracking moment. Use: fe = 27.6 MPa, fpy= 1469 MPa, fpu= 1724 MPa. Aps fps a= 0.85 feb --) M₁ = Aps fps (dp- Mn Mn = Pp fps bdp² (1 -0.59 x P x Ips) fci Apf = 0.85 f (b-bw)h fps Apw = 0.85 bw a fps a= Apwfps 0.85 fobw
Transcribed Image Text:H.W No.1: The concrete I-beam of figure is pretensioned with four bounded stranded cables having total area (371 mm²). Eccentricity of the steel varies parabolically from 0 at the support to 193 mm at the center of 9 m span. The effective stress in steel after losses is 910 MPa. 254 mm 102 mm 76 mm 102 mm 193 mm 9 m a-what superimposed load will produce a balanced condition of external equivalent prestress load, such that uniform axial compression will be obtained in the concrete. b-what superimposed uniform distributed load will produce cracking of the beam, given the modulus of rupture f=3.28 MPa. c-compute the flexural strength of the beam and compare with the cracking moment. Use: fe = 27.6 MPa, fpy= 1469 MPa, fpu= 1724 MPa. Aps fps a= 0.85 feb --) M₁ = Aps fps (dp- Mn Mn = Pp fps bdp² (1 -0.59 x P x Ips) fci Apf = 0.85 f (b-bw)h fps Apw = 0.85 bw a fps a= Apwfps 0.85 fobw
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