Answer both of the following questions precisely, succinctly, and with correct grammar. A. Explain in detail why sodium methoxide (NaOCH,) is more reactive than methanol (HOCH,) in S,2 reactions. Draw two analogous S,2 reactions, one for each reagent, to illustrate your answer.

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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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**Question A:**

Explain in detail why sodium methoxide (NaOCH₃) is more reactive than methanol (HOCH₃) in S<sub>N</sub>2 reactions. Draw two analogous S<sub>N</sub>2 reactions, one for each reagent, to illustrate your answer.

**Question B:**

In principle, the conversion of an alkyl bromide into the corresponding alkene can be accomplished either by an E1 or an E2 pathway. Explain in detail why the E2 mechanism usually is preferred.
Transcribed Image Text:**Question A:** Explain in detail why sodium methoxide (NaOCH₃) is more reactive than methanol (HOCH₃) in S<sub>N</sub>2 reactions. Draw two analogous S<sub>N</sub>2 reactions, one for each reagent, to illustrate your answer. **Question B:** In principle, the conversion of an alkyl bromide into the corresponding alkene can be accomplished either by an E1 or an E2 pathway. Explain in detail why the E2 mechanism usually is preferred.
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Organic reactions proceed via many types of reaction mechanisms. The alkyl halides react via substitution and elimination reaction mechanisms.

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