Write the structural formula of the organic product for the given reaction between an alkyne and an alkyl halide. The alkyne group is shown and should be entered as "CC" without the triple bond. Enter C before associated H atoms (e.g., CH,CH,CH,OCHCHCH,). 1. NANH, CH,CCH CH, CH, CH, CCH, Cн, 2. CH,CH,Br Incorrect

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**Title: Understanding Alkylation Reactions in Organic Chemistry**

**Introduction to Alkylation Reaction:**

In this exercise, we explore the reaction between an alkyne and an alkyl halide. The task is to write the structural formula of the organic product formed during this reaction. 

**Reaction Overview:**

Reactants:
- **Alkyne:** CH₃CCH (Propyne)
- **Reagents:**
  1. NaNH₂ (Sodium amide)
  2. CH₃CH₂Br (Ethyl bromide)

**Instructions:**

1. The alkyne group should be entered as "CC" without the triple bond.
2. Enter the 'C' (carbon) before the associated 'H' (hydrogen) atoms.
   
**Example Format:**

- If a sample compound is CH₃CH₂CH₂OCCHCH₃, it should be formatted as:
  - CH₃CH₂CH₂OCCHCH₃

**Case Study:**

Upon conducting the reaction with the given reagents, the attempted product by the student was entered as:

- **CH₃CH₂CH₂CCH₂CH₃**

This result is marked as **Incorrect**.

**Analysis of the Mistake:**

The error arises from incorrect placement or arrangement of carbon atoms or misunderstanding of the reaction mechanism. It suggests retracing the steps of alkyne reactions, focusing on the regioselectivity and stereochemistry involved.

**Conclusion:**

Understanding the correct formation of the product requires careful consideration of reagent interaction, specifically how the alkyne carbon interacts with sodium amide and the subsequent alkylation.

**Tip for Correct Attempts:**

Review alkyne chemistry and mechanisms, ensuring complete understanding of nucleophilic substitution processes.
Transcribed Image Text:**Title: Understanding Alkylation Reactions in Organic Chemistry** **Introduction to Alkylation Reaction:** In this exercise, we explore the reaction between an alkyne and an alkyl halide. The task is to write the structural formula of the organic product formed during this reaction. **Reaction Overview:** Reactants: - **Alkyne:** CH₃CCH (Propyne) - **Reagents:** 1. NaNH₂ (Sodium amide) 2. CH₃CH₂Br (Ethyl bromide) **Instructions:** 1. The alkyne group should be entered as "CC" without the triple bond. 2. Enter the 'C' (carbon) before the associated 'H' (hydrogen) atoms. **Example Format:** - If a sample compound is CH₃CH₂CH₂OCCHCH₃, it should be formatted as: - CH₃CH₂CH₂OCCHCH₃ **Case Study:** Upon conducting the reaction with the given reagents, the attempted product by the student was entered as: - **CH₃CH₂CH₂CCH₂CH₃** This result is marked as **Incorrect**. **Analysis of the Mistake:** The error arises from incorrect placement or arrangement of carbon atoms or misunderstanding of the reaction mechanism. It suggests retracing the steps of alkyne reactions, focusing on the regioselectivity and stereochemistry involved. **Conclusion:** Understanding the correct formation of the product requires careful consideration of reagent interaction, specifically how the alkyne carbon interacts with sodium amide and the subsequent alkylation. **Tip for Correct Attempts:** Review alkyne chemistry and mechanisms, ensuring complete understanding of nucleophilic substitution processes.
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