5. Both neopentane and n-pentane have a CsH12 formula. Lag ae for interactiom Small area for interaction CH, CH, n-Pentane molar mass = 72.15 g/mol boiling point = 36.1 °C Neopentane molar mass = 72.15 gimol boiling point = 9.5 °Č CH Cí, CH, e n-Pentane 0) Neopentane Cvee tae a. Which compound has a higher boiling point? b. Which compound has stronger London forces? c. What conclusion can be drawn about straight chain and branched chain hydrocarbons from this example?

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Please help answer question 4 and 5

## Model 2: Alkanes and Their Properties

### Table Information
The table lists different alkanes along with their molecular weight, boiling point, and state at room temperature:

- **Methane (CH₄)**
  - Molecular Weight: 16.00 g/mol
  - Boiling Point: -162°C
  - State: Gas

- **Ethane (C₂H₆)**
  - Boiling Point: -89°C
  - State: Gas

- **Propane (C₃H₈)**
  - Boiling Point: -42°C
  - State: Gas

- **Butane (C₄H₁₀)**
  - Boiling Point: 0°C
  - State: Gas

- **Pentane (C₅H₁₂)**
  - Boiling Point: 36°C
  - State: Liquid

- **Hexane (C₆H₁₄)**
  - Boiling Point: 69°C
  - State: Liquid

### Questions and Analysis

1. **Describe the trend in boiling point above.**
   - The boiling point increases as the molecular weight and chain length of the alkanes increase.

2. **Is there a relationship between the boiling point and the molecular weight of the compounds?**
   - Yes, as the molecular weight increases, the boiling point also increases.

3. **What do you attribute the trend we see above as in what does this trend really reflect? Is it the molar mass that is important or something else to this trend?**
   - The trend reflects increasing London dispersion forces as the molecular weight and chain length increase, leading to higher boiling points.

4. **Predict the physical state (solid, liquid, or gas) of the alkane icosane (C₂₀H₄₂) at room temperature. Explain your answer.**
   - Icosane would likely be a solid at room temperature due to its larger molecular weight and stronger intermolecular forces compared to smaller alkanes.

5. **Both neopentane and n-pentane have a C₅H₁₂ formula.**

   - **Structures and Properties:**
     - **n-Pentane:**
       - Molar Mass: 72.15 g/mol
       - Boiling Point: 36.1°C
     -
Transcribed Image Text:## Model 2: Alkanes and Their Properties ### Table Information The table lists different alkanes along with their molecular weight, boiling point, and state at room temperature: - **Methane (CH₄)** - Molecular Weight: 16.00 g/mol - Boiling Point: -162°C - State: Gas - **Ethane (C₂H₆)** - Boiling Point: -89°C - State: Gas - **Propane (C₃H₈)** - Boiling Point: -42°C - State: Gas - **Butane (C₄H₁₀)** - Boiling Point: 0°C - State: Gas - **Pentane (C₅H₁₂)** - Boiling Point: 36°C - State: Liquid - **Hexane (C₆H₁₄)** - Boiling Point: 69°C - State: Liquid ### Questions and Analysis 1. **Describe the trend in boiling point above.** - The boiling point increases as the molecular weight and chain length of the alkanes increase. 2. **Is there a relationship between the boiling point and the molecular weight of the compounds?** - Yes, as the molecular weight increases, the boiling point also increases. 3. **What do you attribute the trend we see above as in what does this trend really reflect? Is it the molar mass that is important or something else to this trend?** - The trend reflects increasing London dispersion forces as the molecular weight and chain length increase, leading to higher boiling points. 4. **Predict the physical state (solid, liquid, or gas) of the alkane icosane (C₂₀H₄₂) at room temperature. Explain your answer.** - Icosane would likely be a solid at room temperature due to its larger molecular weight and stronger intermolecular forces compared to smaller alkanes. 5. **Both neopentane and n-pentane have a C₅H₁₂ formula.** - **Structures and Properties:** - **n-Pentane:** - Molar Mass: 72.15 g/mol - Boiling Point: 36.1°C -
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