An exothermic reaction produces two moles of gas from one mole of solid reactant. Will the reaction be spontaneous? O The reaction will be spontaneous if the magnitude of TArS° is smaller than the magnitude of ArHº. O The reaction will always be spontaneous. O The reaction will never be spontaneous. O The reaction will be spontaneous if the magnitude of TArS° is larger than the magnitude of ArHº.

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An exothermic reaction produces two moles of gas from one mole of solid
reactant. Will the reaction be spontaneous?
The reaction will be spontaneous if the magnitude of TArS° is smaller than the magnitude
of ΔrΗ..
O The reaction will always be spontaneous.
The reaction will never be spontaneous.
O The reaction will be spontaneous if the magnitude of TArS° is larger than the magnitude
of ΔrΗ..
Transcribed Image Text:An exothermic reaction produces two moles of gas from one mole of solid reactant. Will the reaction be spontaneous? The reaction will be spontaneous if the magnitude of TArS° is smaller than the magnitude of ΔrΗ.. O The reaction will always be spontaneous. The reaction will never be spontaneous. O The reaction will be spontaneous if the magnitude of TArS° is larger than the magnitude of ΔrΗ..
TiCl4 (1) → TiCl4 (g)
Using only the appropriate reactions provided in the data below, which one of the
following is the value for the standard entropy change for the reaction above?
Ti(s) + 2 Cl,(g) – TiCl,(1)
Fels) + 3 H,0() —Fe(ОH), (s) + 3/2 H. (в) д.s°- 65.12 Ј К'mol1
A,S° = -224.54 J K-ªmol·1
%3D
TiO,(s) + 4 HCI(g) –TiCl,(g) + 2 H,0(g)
A,S° = -62.20 J Kªmol1
-
%3D
H2(g) + 1/2 O2(g) – H,0(1)
Ti(s) + 2 Cl,(g) – TICI,(g)
A,S° = -163.29J K-mol1
A,S° = -122.04 J Kªmol·1
AS° = -83.85 J K-ªmol1
%3D
Fe,03(s) + 3 H,0(1I)– 2 Fe(OH); (s)
O A,S° = 408.88 J K-1 mol-1
O A,S° = -551.56 J K-1 mol-1
O A,s° = 551.56 J K-1 mol-1
O A,S° = -102.50 J K-1 mol-1
O A,S° = 102.50 J K-1 mol-1
Transcribed Image Text:TiCl4 (1) → TiCl4 (g) Using only the appropriate reactions provided in the data below, which one of the following is the value for the standard entropy change for the reaction above? Ti(s) + 2 Cl,(g) – TiCl,(1) Fels) + 3 H,0() —Fe(ОH), (s) + 3/2 H. (в) д.s°- 65.12 Ј К'mol1 A,S° = -224.54 J K-ªmol·1 %3D TiO,(s) + 4 HCI(g) –TiCl,(g) + 2 H,0(g) A,S° = -62.20 J Kªmol1 - %3D H2(g) + 1/2 O2(g) – H,0(1) Ti(s) + 2 Cl,(g) – TICI,(g) A,S° = -163.29J K-mol1 A,S° = -122.04 J Kªmol·1 AS° = -83.85 J K-ªmol1 %3D Fe,03(s) + 3 H,0(1I)– 2 Fe(OH); (s) O A,S° = 408.88 J K-1 mol-1 O A,S° = -551.56 J K-1 mol-1 O A,s° = 551.56 J K-1 mol-1 O A,S° = -102.50 J K-1 mol-1 O A,S° = 102.50 J K-1 mol-1
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