At 25 °C, the equilibrium partial pressures for the reaction A(g) + 2 B(g) 4C(g) + D(g) were found to be PA = 5.52 bar, PB What is the standard change in Gibbs free energy of this reaction at 25 °C? AGixn = = 5.96 bar, Pc 5.11 bar, and Pp = 5.82 bar. kJ/mo
At 25 °C, the equilibrium partial pressures for the reaction A(g) + 2 B(g) 4C(g) + D(g) were found to be PA = 5.52 bar, PB What is the standard change in Gibbs free energy of this reaction at 25 °C? AGixn = = 5.96 bar, Pc 5.11 bar, and Pp = 5.82 bar. kJ/mo
Chemistry
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ISBN:9781305957404
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Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Equilibrium Partial Pressures and Gibbs Free Energy Change**
At 25 °C, the equilibrium partial pressures for the reaction:
\[ A(g) + 2 B(g) \rightleftharpoons 4 C(g) + D(g) \]
were found to be \( P_A = 5.52 \, \text{bar} \), \( P_B = 5.96 \, \text{bar} \), \( P_C = 5.11 \, \text{bar} \), and \( P_D = 5.82 \, \text{bar} \).
**Problem:**
What is the standard change in Gibbs free energy of this reaction at 25 °C?
\[ \Delta G^\circ_{\text{rxn}} = \]
*Note: The empty box indicates where the answer should be calculated in kJ/mol.*](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3fedbef1-4110-4bb3-9906-fd5663476380%2F7ce615c8-f730-46ac-be48-dc7d14e1eb6d%2Fittt97i_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Equilibrium Partial Pressures and Gibbs Free Energy Change**
At 25 °C, the equilibrium partial pressures for the reaction:
\[ A(g) + 2 B(g) \rightleftharpoons 4 C(g) + D(g) \]
were found to be \( P_A = 5.52 \, \text{bar} \), \( P_B = 5.96 \, \text{bar} \), \( P_C = 5.11 \, \text{bar} \), and \( P_D = 5.82 \, \text{bar} \).
**Problem:**
What is the standard change in Gibbs free energy of this reaction at 25 °C?
\[ \Delta G^\circ_{\text{rxn}} = \]
*Note: The empty box indicates where the answer should be calculated in kJ/mol.*
![For a particular reaction, \( \Delta H^\circ = -46.7 \, \text{kJ/mol} \) and \( \Delta S^\circ = -123.8 \, \text{J/(mol} \cdot \text{K)} \). Assuming these values change very little with temperature, at what temperature does the reaction change from nonspontaneous to spontaneous in the forward direction?
\[ T = \, \text{_____________ K} \]
Is the reaction in the forward direction spontaneous at temperatures greater than or less than the calculated temperature?
- O greater than
- O less than](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3fedbef1-4110-4bb3-9906-fd5663476380%2F7ce615c8-f730-46ac-be48-dc7d14e1eb6d%2Fiyg16u_processed.jpeg&w=3840&q=75)
Transcribed Image Text:For a particular reaction, \( \Delta H^\circ = -46.7 \, \text{kJ/mol} \) and \( \Delta S^\circ = -123.8 \, \text{J/(mol} \cdot \text{K)} \). Assuming these values change very little with temperature, at what temperature does the reaction change from nonspontaneous to spontaneous in the forward direction?
\[ T = \, \text{_____________ K} \]
Is the reaction in the forward direction spontaneous at temperatures greater than or less than the calculated temperature?
- O greater than
- O less than
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