At 25 °C, the equilibrium partial pressures for the reaction 3 A(g) + 2 B(g) = C(g) + 2 D(g) were found to be PA = 4.25 atm, Pg = = 5.05 atm, Pc = 4.13 atm, and Pp = 4.94 atm. %3D What is the standard change in Gibbs free energy of this reaction at 25 °C? kJ AGixn %3D mol

At 25 °C, the equilibrium partial pressures for the reaction 3 A(g) + 2 B(g) = C(g) + 2 D(g) were found to be PA = 4.25 atm, Pg = = 5.05 atm, Pc = 4.13 atm, and Pp = 4.94 atm. %3D What is the standard change in Gibbs free energy of this reaction at 25 °C? kJ AGixn %3D mol

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

See similar textbooks

Related questions

Q: The equilibrium constant for the formation of CO2(g) at a temperature T is given by the 13275.6…

A: Since you have posted multiple questions, we are entitled to answer the first only.

Q: At 25 ∘C, the equilibrium partial pressures for the reaction A(g)+2B(g)↽−−⇀C(g)+D(g) were found…

Q: Calculate ΔG° rxn for the reaction below given the Gibbs free energies of formation.

Q: For a certain chemical reaction, the standard Gibbs free energy of reaction is 139. kJ. Calculate…

Q: For a certain chemical reaction, the standard Gibbs free energy of reaction is -87.1 kJ. Calculate…

A: The standard Gibbs free energy of the reaction = -87.1 kJ = -87100 JThe equilibrium constant of the…

Q: 7. Please calculate the standard Gibbs free energy of reaction of the following chemical equation at…

Q: At 25 °C, the equilibrium partial pressures for the reaction 3 A(g) + 3 B(g) = C(g) + 3 D(g) were…

A: Given-> 3A(g) + 3B(g) ----> C(g) + 3D(g) PA= 5.75atm PB= 4.26 atm PC= 5.63 atm PD= 4.88 atm T=…

Q: For a gaseous reaction, standard conditions are 298 K and a partial pressure of 1 atm for all…

A: The equilibrium reaction given is, => C2H6 (g) + H2 (g) ↔ 2 CH4 (g) Given: Temperature = 298 K…

Q: For a gaseous reaction, standard conditions are 298 K and a partial pressure of 1 atm for all…

A: Given that: ∆Go=-32.8 KJ/mol T = 298 K PN2=0.200 atm PH2 = 0.400 atm PNH3 = 0.900 atm To find, ∆G…

Q: Σ II For a gaseous reaction, standard conditions are 298 K and a partial pressure of 1 atm for all…

Q: ST3D.3- At constant temperature and pressure, what is the minimum mass [in g] of glucose needed for…

A: Answer: Value of gibbs free energy change is always equal to non-expansion work and over here…

Q: What is the standard change in Gibbs free energy of this reaction at 25 °C?

Q: Calculate the standard entropy, Δ?∘rxn, of the reaction at 25.0 ∘C using the table of thermodynamic…

Q: For a gaseous reaction, standard conditions are 298 K and a partial pressure of 1 bar for all…

Q: Calculate the change in the Gibbs energy for the reaction below, at 25.0 °C 2 Ca(s) + O2(g) → 2…

A: The formula for Gibbs free energy change is written as - ∆G° = ∆H° - T∆S° Where - ∆G° = Gibbs free…

Q: For a gaseous reaction, standard conditions are 298 K and a partial pressure of 1 atm for all…

Q: Adenosine triphosphate (ATP) is a compound that provides energy for biomechanical reactions in the…

A: Given: ΔH = -20.0 KJ/mol = -20000 J/mol. And ΔS = 34.0 J/K.

Q: For a certain chemical reaction, the standard Gibbs free energy of reaction is 128. kJ. Calculate…

Q: For a gaseous reaction, standard conditions are 298 K and a partial pressure of 1 atm for all…

A: Information of question

Q: For a certain chemical reaction, the standard Gibbs free energy of reaction is -99.3 kJ. Calculate…

A: to calculate the temperature, we will use the formula which related Gibbs free energy and the…

Q: For a gaseous reaction, standard conditions are 298 K and a partial pressure of 1 atm for all…

A: Gibbs free energy ∆G = ∆G° + RTln Q formula used

Q: The equilibrium constant at 2.40 x 10² °C for the equation PCI, (g) PC13(g) + Cl₂(g) is Kp = 4.50 x…

A: Temparature = 240 0C = 240 0C + 273=513k Kp = 4.50 ×103 Gas constant (R) = 8.314 J/k mol

Q: We start with a pure sample of A(g). The following equilibrium is established: 2 A(g) B(g) + C(g)…

A: Given: Total pressure (PT) is 8.56 atm. Partial pressure of A is 5.43 atm.

Q: For this reactior

A: Dear student this question is related to equilibrium concept.

Q: For a certain chemical reaction, the standard Gibbs free energy of reaction is 83.4 kJ. Calculate…

A: Given that, ∆G°= 83.4 KJ = 83400 J K= 2.4×10-15 T = ?

Q: N2(g) + 202(g) → 2NO2(g) AH = +66.4 kJ Complete the table for Reaction 3. Assume the process occurs…

Q: 10 For a certain chemical reaction, the equilibrium constant K = 3.4 × 10º at 30.0 °C. Calculate the…

A: The relationship between standard Gibbs free energy change (∆G°) of reaction and equilibrium…

Q: Discuss the spontaneity of each process in the following scenarios, based on the use of the Gibbs…

A: The spontaniety of Reaction depends upon the sign of ∆G value for the reaction . The reaction is…

Q: A reaction vessel was filled with H2, CO2, CO, and Molar H20 and the following reaction occurred. H2…

Q: For a gaseous reaction, standard conditions are 298 K and a partial pressure of 1 atm for all…

A: Given: PNO=0.500 atm PO2=0.350atm PNO2=0.800atm ∆Go=-32.8kJ/mol

Q: What is the ΔrG for the following reaction (in kJ mol-1) at 298 K? 3 O2 (g) ⇌ 2 O3 (g) The…

A: Standard Gibbs free energy of formation of O2(g), ∆Gfo(O2, g) = 0.00 kJ.mol-1 Standard Gibbs free…

Q: For a certain chemical reaction, the standard Gibbs free energy of reaction is 117. kJ. Calculate K…

Q: For a gaseous reaction, standard conditions are 298 K and a partial pressure of 1 atm for all…

Q: Calculate the standard entropy, AS ixn, of the reaction at 25.0 °C using the table of thermodynamic…

A: The objective of the question is to determine the a) Standard entropyb) Standard Gibbs free energy…

Q: At -8.60 °C the concentration equilibrium constant K = 3.8 x 10 for a certain reaction. Here are…

A: The details of the answers is shown below.Explanation:Step 1:

Q: The standard Gibbs free energy change is 2.60 kJ/mol for the reaction at 25.0oC: H2(g) + I2(g) →←…

A: Given: H2(g) + I2(g) →← 2HI(g); ∆Gorxn = + 2.60 kJ/mol

Q: At 25 ∘C , the equilibrium partial pressures for the reaction 3A(g)+4B(g)↽−−⇀2C(g)+2D(g) were…

Q: For a gaseous reaction, standard conditions are 298 K and a partial pressure of 1 atm for all…

Q: For the reaction CO₂(g) + H₂(g) → CO(g) + H₂O(g) = : 41.2 kJ and AS⁰ = 42.1 J/K ΔΗ° The equilibrium…

Q: The reaction C6H12O6 + 6O2 → 6CO2 + 6H2O ΔHo = −1072 kJ/mol and ΔSo =…

A: For the given reaction, ∆H° = -1072 kJ /mol = -1072 × 103 J mol-1 ∆S° = 578 J K-1 mol-1 T = 37 ℃ =…

Q: Σ At 25 °C, the equilibrium partial pressures for the reaction 3 A(g) + 4 B(g) =2C(g)+2 D(g) %3D…

Q: Carbon monoxide and nitrogen monoxide gases combine to form carbon dioxide and nitrogen gases…

Q: a) Describe in your own words the relationship between standard change in Gibbs free energy…

A: a) The relationship between the ΔG0 and equilibrium constant is given by => RTln(Keq ) = -ΔG0…

Q: When a neutralization reaction was carried out using 100.0 mL of 0.7890M NH3 water and 100.0 mL of…

A: Given: Volume of NH3 = Volume of acetic acid = 100 mL Concentration of NH3 = 0.7890 M Concentration…

Q: For the reaction: 1A(g) + 4B(g) = 2C(g) + 2D(g) where K, = 9.483 · 103 the gaseous components are…

A: The reaction taking place is given as, => A (g) + 4 B (g) -------> 2 C (g) + 2 D (g)…

Question

At 25 °C, the equilibrium partial pressures for the reaction
3 A(g) + 2 B(g) = C(g) + 2 D(g)
were found to be PA = 4.25 atm, Pg = 5.05 atm, Pc
= 4.13 atm, and Pp
4.94 atm.
%3D
What is the standard change in Gibbs free energy of this reaction at 25 °C?
kJ
mol

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Step by step

Solved in 2 steps with 2 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.

Similar questions

Calculate the standard entropy, ASixn, of the reaction at 25.0 °C using the table of thermodynamic properties. C₂H₂(g) + H₂O(1) C₂H₂OH(1) ASixn -1.3 ×10² = Calculate the standard Gibbs free energy of the reaction, AGixn. The standard enthalpy of the reaction, AHin, is -44.2 kJ.mol-¹. AGixn = -5.5 Incorrect J.K¯¹·mol¯¹ kJ.mol
Km.201.
For a certain chemical reaction, the standard Gibbs free energy of reaction at 15.0 °C is 147. kJ . Calculate the equilibrium constant K for this reaction.Round your answer to 2 significant digits.
When a neutralization reaction was carried out using 100.0 mL of 0.7890M NH3 water and 100.0 mL of 0.7940M acetic acid, ΔT was found to be 4.76 °C. The specific heat of the reaction mixture was 4.104 J g-l K-1 and its density was 1.03 g mL-1. The calorimeter constant was 3.36 JK-1 a) Calculate ΔH neutralization for the reaction of NH3 and acetic acid. b) At the end of the experiment, it was discovered that the thermometer had not been calibrated. When it was calibrated, it was found that the thermometer read 0.50 °C low. What effect would this thermometer reading have on the reported DH neutralization calculated above? c) When the temperature-time data graph was reviewed, it was found that an error had been made in determining ΔT. Instead of 4.76 °C, ΔT was actually 4.70 °C. Based on this change only, calculate the correct ΔH neutralization for the reaction of NH3, and acetic acid. d) Calculate the percent error for the correct ΔH neutralization if aΔ DT of 4.76 °C had been used.…
For a certain chemical reaction, the standard Gibbs free energy of reaction is - 104. kJ. Calculate the temperature at which the equilibrium constant K = 7.1 × 10¹8. Round your answer to the nearest degree. T = °C X S
For a gaseous reaction, standard conditions are 298 K and a partial pressure of 1 atm for all species. For the reaction N, (g) + 3 H, (g) 2 NH,(g) the standard change in Gibbs free energy is AG° = -32.8 kJ/mol. What is AG for this reaction at 298 K when the partial pressures are PN, = 0.500 atm, Pi, = 0.100 atm, and PNH, = 0.600 atm? AG = kJ/mol
For a gaseous reaction, standard conditions are 298 K and a partial pressure of 1 atm for all species. For the reaction N₂(g) + 3 H₂(g) ⇒ 2NH₂(g) the standard change in Gibbs free energy is AG° = −32.8 kJ/mol. What is AG for this reaction at 298 K when the partial pressures are PN₂ = 0.100 atm, PH₂ = 0.100 atm, and PNH₂ = 0.750 atm? AG = 737 kJ/mol
Rt is 0.616 T is 37c G=G+RT * ln(k)
At 25 °C, the equilibrium partial pressures for the reaction 3 A(g) + 4 B(g) 2C(g) + 2D(g) were found to be PA = 4.67 atm, På = 5.73 atm, Pc = 5.60 atm, and Pp = 5.84 atm. What is the standard change in Gibbs free energy of this reaction at 25 °C? kJ mol privacy policy contact us help terms of use 6:11 PM about us careers 3/25/202
For a gaseous reaction, standard conditions are 298 K and a partial pressure of 1 atm for all species. For the reaction C₂H(g) + H₂(g) = 2 CH₂(g) the standard change in Gibbs free energy is AG° = -69.0 kJ/mol. What is AG for this reaction at 298 K when the partial pressures are PC₂H₂ = 0.350 atm, PH₂ = 0.500 atm, and PCH, = 0.950 atm? AG = kJ/mol
Calculate the value of Kp for the equation C(s) + CO,(g) = 2 CO(g) Kp = ? given that at a certain temperature C(s) + 2 H,O(g) = CO,(g) + 2 H,(g) Ки — 3.15 H,(g) + CO,(g) H,0(g)+CO(g) Kp2 = 0.747 Kp =
For a certain chemical reaction, the standard Gibbs free energy of reaction is -133. kJ. Calculate the temperature at which the equilibrium constant K = 8.2 x 10- 22 Round your answer to the nearest degree. T= \| °C