A reaction has AH°= 100 kJ/mol and AS°= 250 J/mol.K. Is the reaction spontaneous at room temperature? If not, unde what temperature conditions will it become spontaneous?
A reaction has AH°= 100 kJ/mol and AS°= 250 J/mol.K. Is the reaction spontaneous at room temperature? If not, unde what temperature conditions will it become spontaneous?
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![### Spontaneity of a Chemical Reaction
A chemical reaction has the following thermodynamic parameters:
- **ΔH° (Enthalpy change)** = 100 kJ/mol
- **ΔS° (Entropy change)** = 250 J/mol·K
The problem posed is:
- **Question**: Is the reaction spontaneous at room temperature? If not, under what temperature conditions will it become spontaneous?
### Explanation
To determine if a reaction is spontaneous, we use the Gibbs free energy equation:
\[ \Delta G° = \Delta H° - T \Delta S° \]
Where:
- \(\Delta G°\) is the change in Gibbs free energy.
- \(\Delta H°\) is the change in enthalpy.
- \(T\) is the temperature in Kelvin.
- \(\Delta S°\) is the change in entropy.
A reaction is spontaneous if \(\Delta G° < 0\).
### Step-by-Step Solution
1. **Convert Units:**
Make sure that the units for ΔH° and ΔS° are compatible. ΔS° is given in J/mol·K, while ΔH° is in kJ/mol. Convert ΔH° to J/mol:
\[ \Delta H° = 100 \text{ kJ/mol} \times 1000 \text{ J/kJ} = 100,000 \text{ J/mol} \]
2. **Set Up Gibbs Free Energy Equation:**
Substitute the values into the equation \(\Delta G° = \Delta H° - T \Delta S°\):
\[ \Delta G° = 100,000 \text{ J/mol} - T \times 250 \text{ J/mol·K} \]
3. **Determine Spontaneity at Room Temperature:**
Assume room temperature is approximately 298 K. Substitute T = 298 K into the equation:
\[ \Delta G° = 100,000 \text{ J/mol} - 298 \text{ K} \times 250 \text{ J/mol·K} \]
\[ \Delta G° = 100,000 \text{ J/mol} - 74,500 \text{ J/mol} \]
\[ \Delta G° = 25,500 \text{ J/mol} \]
Since \(\Delta G° >](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff90913a8-510d-485a-8226-8a0b61f2c858%2Ff8d93ced-a881-4940-bc01-9076ae9af454%2Frgh1kvv_processed.png&w=3840&q=75)
Transcribed Image Text:### Spontaneity of a Chemical Reaction
A chemical reaction has the following thermodynamic parameters:
- **ΔH° (Enthalpy change)** = 100 kJ/mol
- **ΔS° (Entropy change)** = 250 J/mol·K
The problem posed is:
- **Question**: Is the reaction spontaneous at room temperature? If not, under what temperature conditions will it become spontaneous?
### Explanation
To determine if a reaction is spontaneous, we use the Gibbs free energy equation:
\[ \Delta G° = \Delta H° - T \Delta S° \]
Where:
- \(\Delta G°\) is the change in Gibbs free energy.
- \(\Delta H°\) is the change in enthalpy.
- \(T\) is the temperature in Kelvin.
- \(\Delta S°\) is the change in entropy.
A reaction is spontaneous if \(\Delta G° < 0\).
### Step-by-Step Solution
1. **Convert Units:**
Make sure that the units for ΔH° and ΔS° are compatible. ΔS° is given in J/mol·K, while ΔH° is in kJ/mol. Convert ΔH° to J/mol:
\[ \Delta H° = 100 \text{ kJ/mol} \times 1000 \text{ J/kJ} = 100,000 \text{ J/mol} \]
2. **Set Up Gibbs Free Energy Equation:**
Substitute the values into the equation \(\Delta G° = \Delta H° - T \Delta S°\):
\[ \Delta G° = 100,000 \text{ J/mol} - T \times 250 \text{ J/mol·K} \]
3. **Determine Spontaneity at Room Temperature:**
Assume room temperature is approximately 298 K. Substitute T = 298 K into the equation:
\[ \Delta G° = 100,000 \text{ J/mol} - 298 \text{ K} \times 250 \text{ J/mol·K} \]
\[ \Delta G° = 100,000 \text{ J/mol} - 74,500 \text{ J/mol} \]
\[ \Delta G° = 25,500 \text{ J/mol} \]
Since \(\Delta G° >
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