о Example: What is the temperature range in which the following reaction is spontaneous? N₂+ 3H2 → 2NH3 S N2(g) 191.5 J/mol K SH2(g) 130.6 J/mol K о S NH3(g) 192.5 J/mol K AH, N2(g) = 0 kJ/mol AH, H2(g) 0 kJ/mol AH, NH3(g) = -46.19 kJ/mol

о Example: What is the temperature range in which the following reaction is spontaneous? N₂+ 3H2 → 2NH3 S N2(g) 191.5 J/mol K SH2(g) 130.6 J/mol K о S NH3(g) 192.5 J/mol K AH, N2(g) = 0 kJ/mol AH, H2(g) 0 kJ/mol AH, NH3(g) = -46.19 kJ/mol

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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For each of the following reactions indicate whether as written it will be spontaneous at all temperature only at high enough temperatures only at low temperatures not at any temperatures or if the given information is insufficient to draw a conclu
What is the temperature range in which the following reaction is spontaneous? N₂+ 3H2 → 2NH3 S N2(g) 191.5 J/mol K S H2(g) 130.6 J/mol K S NH3(g) 192.5 J/mol K AH, N2(g) 0 kJ/mol AH, H2(g) 0 kJ/mol AH, NH3(g) -46.19 kJ/mol
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For a particular chemical reaction H = 6.8 kJ and S = –29 J/K. Under what temperature condition is the reaction spontaneous?
A chemical engineer is studying the two reactions shown in the table below. In each case, he fills a reaction vessel with some mixture of the reactants and products at a constant temperature of 63.0 °C and constant total pressure. Then, he measures the reaction enthalpy AH and reaction entropy AS of the first reaction, and the reaction enthalpy AH and reaction free energy AG of the second reaction. The results of his measurements are shown in the table. Complete the table. That is, calculate AG for the first reaction and AS for the second. (Round your answer to zero decimal places.) Then, decide whether, under the conditions the engineer has set up, the reaction is spontaneous, the reverse reaction is spontaneous, or neither forward nor reverse reaction is spontaneous because the system is at equilibrium.
The vaporization of compound A is described by the following chemical equation. A(1) A(g) AH vap (78.97 °C) = 37.87 kJ/mol Calculate the entropy of vaporization, A.Svap, for A(1) at 25.0 °C given that the boiling point of A is 78.97 °C, and the molar heat capacity of A(1) is 114.29 J/(mol K). Assume that the molar heat capacity of A(g) is 55.9% of that of A(1). ASvap = Calculate the standard enthalpy of vaporization, AHvap, for A(1) at 25.0 °C. AH vap = Calculate tl AG'vap = x10 TOOLS of vaporization, AGvap, at 25.0 °C. Determine the equilibrium constant K for the va 1970ea J. mol-1. K-1 kJ/mol kJ/mol
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A reaction has AH°= 100 kJ/mol and AS°= 250 J/mol.K. Is the reaction spontaneous at room temperature? If not, under what temperature conditions will it become spontaneous?
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