The enthalpy and entropy changes for a reaction at 298 K are ∆H = 46 kJ and ∆S = 190 J/K. Which of the following best describes this reaction A) The reaction is spontaneous and driven by favorable changes in the enthalpy and entropy. B) The reaction is not spontaneous because heat is absorbed. C) The reaction is not spontaneoius but could be spontaneous at a higher temperature. D) The reaction is spontaneous and driven by the favorable entropy change.

Q: A chemical reaction has a standard entropy change, ΔSo, of -287.8 J/(molK) and a standard enthalpy…

A: The given data you have - ΔSo = -287.8 J/K-mol ΔHo =  -138.1 kJ/mol

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Q: How temperature determines spontaneity for reactions in which ∆S and ∆H have the same sign

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Q: The enthalpy for a certain process is 121.9 kJ/mol and the entropy for the process is 454.8 J/K.  At…

A: We are given that, ∆H = 121.9 KJ/mol = 121.9 × 10^3 J/mol  ∆S = 454.8 J/K

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Q: The Second Law of Thermodynamics states, the entropy of the universe is always increasing, ∆Suni >…

A: Spontaneous Reactions: The reactions that occur spontaneously i.e without any addition of external…

Q: Consider this reaction: N2 (s) + 2 02 (g)→ 2NO2 (g) AS° = -121.77 J/K.mol; AH° = %3! 66.36 kJ/mol…

A: From the given question it is given that, ΔSo < 0 ΔH0 > 0

Q: at what temperature will this reaction be exactly at equilibrium?

A: Enthalpy change (∆Ho)=-162.2 kJ =-162.2  X 103J Entropy change (∆So)=104.2 J/K ∆Go=0 at equilibrium…

Q: Above what temperature does the following reaction become nonspontaneous? 2 H2S(g) +3 02(g) - 2…

A: Given, The balanced chemical equation is given below, 2H2O(g)+3O2(g)→2SO2(g)+2H2O(g) Then, ∆H=-1036…

Q: A) AG becomes less negative and the reaction becomes less spontaneous. B) AG becomes more negative…

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Q: At what temperature will a reaction become spontaneous, if its AS is +100.3 J/mol and AH° is +48.90…

A: Given : ΔSo = 100.3 J/mol. And ΔHo = 48.90 KJ/mol = 48900 J/mol.…

Q: How ΔGo is related to ΔHo and ΔSo . Illustrate by Equation ?

A: Given terms,    ΔGo , ΔHo and ΔSo  G - free energy H - enthalpy S - entropy

Q: The ∆H and ∆S for the decomposition of sulfur tetrabromide to sulfur and liquid bromine is +115 kJ…

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Q: For a certain reaction, ΔH = -35.4 kJ/mol and ΔS = -85.5 J/K mol. Is this reaction endothermic or…

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Q: Gibbs Free Energy Third Law of Thermodynamics Directions: Answer the following items 1. Calculate…

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Q: Consider the following reaction: 2 O3(g)  →  3 O2(g)    ΔS∘∘ = 137.4 J/K;  ΔH∘∘ = −285.4 kJ…

A: To calculate ΔGo for the given reaction.

Q: Consider the following half-reactions: F2(g) + 2 e ® 2 F(aq) E° = +2.87 V Cu2+(aq) + 2 e ® Cu(s)…

A: You have asked multiple type questions, we will solve only first  questions for you. If you want any…

Q: For a particular reaction, Δ?∘=−28.4 kJ/mol and Δ?∘=−87.9 J/(mol⋅K). Assuming these values change…

A: Given: ΔHo = -28.4 KJ/mol = -28400 J/mol. And the value of ΔSo = -87.9 J/mol.K.

Q: 1: Above what temperature does the following reaction become nonspontaneous? FeO(s) + CO(g) → →…

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Q: 2.1.1 Calculate ∆rGo , using only Gibbs energy values. 2.1.2 Calculate the equilibrium constant, K,…

A: Given that -  1/4 S8 (s) + 3O2(g) → 2SO3 (g)    (2.1.1) -    Then, Gibbs free energy is -  ∆G°rxn =…

Q: An example of a reaction where ∆G = 0 is   C(graphite)→C(diamond)   any synthesis reaction…

A: We know, The value of  ∆G = 0 when the reaction is at an equilibrium.

Q: A particular reaction has a ΔHo value of -150 kJ and ΔSo of -393 J/mol K at 298 K. Assuming that ΔHo…

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Q: Calculate the standard free energy change (kJ/mol) for the reaction shown at a temperature of 298.15…

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Q: Calculate the free energy change for this reaction at 25 °C. Determine if the reaction is…

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Q: 2) Given the following information, determine at what temperature the following reaction becomes…

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Q: The enthalpy and entropy changes for a reaction at 298 K are ∆H = -102 kJ and ∆S = -208 J/K. Which…

A: Given:  ∆H = -105 kJ;       ∆S = -208 J/K;       T = 298 K∆G = ∆H-T∆S∆G = -105 kJ - (298 K) (-0.208…

Q: For which set of conditions will a reaction not be spontaneous at all temperatures?   A ΔHrxn > 0;…

A: The formula is  ΔG = ΔH - TΔS The reaction is spontaneous if ΔG < 0 The reaction is…

Q: Consider the following reaction at 25 °C: 5 SO₃(g) + 2 NH₃(g) → 2 NO(g) + 5 SO₂(g) + 3 H₂O(g) a)…

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Q: For the reaction 2 NH3 (g) --> N2 (g)+ 3 H2 (g) , ∆H = +92 kJ. Which of the following is true?…

A: The given reaction is,  2 NH3 (g) --> N2 (g)+ 3 H2 (g) , ∆H = +92 kJ ∆H is positive, that means…

Q: For a reaction in which ∆H = 76.2 kJ/mol and ∆S = 422 J/K mol, determine the temperature, in °C,…

A: We have the equation for Gibbs free energy as, ∆G = ∆H-T∆S Where, ∆G = change in Gibbs energy ∆H =…

Q: Consider the synthesis of sulphur trioxide from its elements at 25oC: 1/4 S8 (s) + 3O2(g) → 2SO3 (g)…

A: Given reaction is  1/4 S8 (s) + 3O2(g) → 2SO3 (g) Given thermodynamic data is  Species…

Q: Consider the synthesis of sulphur trioxide from its elements at 25oC: 1/4 S8 (s) + 3O2(g) → 2SO3 (g)…

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Q: Calculate the ∆H and ∆G for the following reactions at 25 degrees Celsius: Al2O3 (s) + 2Fe (s) —>…

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Q: Consider the reaction: NH4Cl (s) → NH3 (g) + HCl (g) ArS 94.6 J K-¹mol-¹ A,H= 175.98 kJ/mol a)…

A: Since you have posted a question with multiple sub-parts, we will solve first three sub-parts for…

Q: Octane 1C8H182 is a liquid hydrocarbon at room temperature that is a constituent of gasoline.…

A: We have the equation ∆G°=∆H°-T∆S° Where ∆H° is change in enthalpy, ∆G° is change in free energy, T…

Q: What is ∆Gο at 25° for the reaction: 2 CO (g) + 2 H2 (g) → CO2(g) + CH4(g), given that at 25° ∆Hο =…

A: Recall data, ∆H°=-247.3 KJ mol-1 ∆S°=-256.5 J mol-1K-1= -0.2565 KJ mol-1K-1 ∆G°=?

Q: Example: What is the temperature range in which the following reaction is spontaneous?N2 + 3H2 →…

A: Step 1:Step 2:

Q: Consider the synthesis of sulphur trioxide from its elements at 25°C: S8(s) + 30za) 2503 (g)

A: Given reaction is :  Change in entropy of surrounding = ∆Ssurr = ?  Change in entropy of universe =…

Q: Consider the following reaction: 2 AB2 (g) ⟶ 2 AB(g) + B2(g)           ΔHo= +480.0 kJ/mol a.) Do…

A: Given Chemical Reaction is -  2 AB2 (g) ⟶ 2 AB(g) + B2(g)           ΔH° = +480.0 kJ/mol  Here the…