An article presents a study of the failure pressures of roof panels. Following are the failurepressures, in kPa, for five panels constructed with 6d smooth shank nails. These data are consistentwith means and standard deviations presented in the article3.32 2.460 3.45 2.38 3.01Find a 95% confidence interval for the mean failure pressure for this type of roof panel. (Round thefinal answers to three decimal places.)The 95% confidence interval is (2.6723.175).

The failure pressures of roof panels are given as follows:3.32, 2.460, 3.45, 2.38, and 3.01.It is…

Answered: An article presents a study of the…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Consider the following measures based on independently drawn samples from normally distributed populations: (You may find it useful to reference the appropriate table: chi-square table or F table) Sample 1: s = 241, and n1 = 26 Sample 2: s = 220, and n2 = 16 a. Construct the 95% interval estimate for the ratio of the population variances. (Round "F" value and final answers to 2 decimal places.) Confidence interval to b. Using the confidence interval from Part (a), test if the ratio of the population variances differs from 1 at the 5% significance level. The 95% confidence interval the value 1. Thus, we conclude that the population variances differ at the 5% significance level.
Here are summary statistics for randomly selected weights of newborn girls: n = 36, x= 3216.7 g, s = 688.5 g. Use a confidence level of 99% to complete parts (a) through (d) below. a. Identify the critical value to/2 used for finding the margin of error. ta/2 (Round to two decimal places as needed.) b. Find the margin of error. = = g (Round to one decimal place as needed.) c. Find the confidence interval estimate of μ. g<μ< g (Round to one decimal place as needed.) d. Write a brief statement that interprets the confidence interval. Choose the correct answer below. O A. One has 99% confidence that the sample mean weight of newborn girls is equal to the population mean weight of newborn girls. B. Approximately 99% of sample mean weights of newborn girls will fall between the lower bound and the upper bound. C. One has 99% confidence that the interval from the lower bound to the upper bound contains the true value of the population mean weight of newborn girls. D. There is a 99% chance…
A recent study of high school students shows the percentage of females and males who have an after-school job. A simple random sample of high school students was interviewed. The students were asked whether they worked after school. Of the 250 females, 58 answered yes, as did 113 of the 380 males. Part A: Construct and interpret a 95% confidence interval for the difference in population proportions of females and males who have an after-school job. Be sure to state the parameter, check conditions, perform calculations, and make conclusion(s). Part B: Does your interval from part A give convincing evidence of a difference between the population proportions? Explain.
1. In a test of the effectiveness of garlic for lowering cholesterol, 43 subjects were treated with garlic processed tablet form. Cholesterol levels were measured before and after the treatment. The chang (before-after) in their levels of LDL cholesterol (in mg/dL) have a mean of 4.2 and a standard devia 19.4. Construct a 99% confidence interval estimate of the mean net change in LDL cholesterol after garlic treatment. What does the confidence interval suggest about the effectiveness of garlic in redu LDL cholesterol?
In the following Table are gradients for eight female teeth and eight male teeth. These numbers are measures of the rate of change in the amount of X-ray penetration through a 500-micron section of tooth enamel at a wavelength of 600 nm as opposed to 400 nm. Find the 95% confidence interval for lx - ly. Hint(to.025,14 =2.1448) Male Xi 4.9 5.4 4.8 5.3 5.0 5.5 5.4 6.6 6.3 4.3 Female y; 3.7 4.1 5.6 4.0 3.6 5.0
Here are summary statistics for randomly selected weights of newborn girls: n=218, x=32.8hg,s=6.2hg. Construct a confidence interval estimate of the mean. Use a 90% confidence level. Are these results very different from the confidence interval 32.0hg <μ<33.4 hg with only 20 sample values, x=32.7hg, and s=1.8hg? What is the confidence interval for the population mean μ?_____hg <μ<___hg Are the results between the two confidence intervals very different?
One method for measuring air pollution is to measure the concentration of carbon monoxide, or CO, in the air. Suppose Nina, an environmental scientist, wishes to estimate the CO concentration in Zagreb, Croatia. She randomly selects 45 locations throughout the city measures the CO concentration at each location. Based on her 45 samples, she computes the margin of error for a 95% t-confidence interval for the mean concentration of CO in Zagreb, in µg/m³, to be 4.28. What would happen to the margin of error if Nina decreases the confidence level to 90%? Nina increases the confidence level to 99%? Nina decreases the sample size to 33 locations? Nina increases the sample size to 65 locations? Answer Bank Increase Stay the same Decrease
Consider the following data drawn independently from normally distributed populations: (You may find it useful to reference the appropriate table: z table or t table) X₁ = -28.3 2 $1 n1 = 22 = 8.7 X2 = -18.5 2 S2 = 7.9 n2 = 16 a. Construct the 95% confidence interval for the difference between the population means. Assume the population variances are unknown but equal. (Round final answers to 2 decimal places.) Confidence interval is to
Here are summary statistics for the weights of Pepsi in randomly selected cans: n=36, x=0.82412 lb, s=0.00573 lb. Use a confidence level of 95% to complete parts (a) through (d) below. Part 1 a. Identify the critical value tα/2 used for finding the margin of error. tα/2 = Part 2 b. Find the margin of error. Part 3 c. Find the confidence interval estimate of Part 4 d. Write a brief statement that interprets the confidence interval.

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